gawk

问题 I have strftime format of time, let's say (%Y-%m-%d %H:%M:%S) and a file which should contain this kind of data e.g. (2012-02-11 17:15:00) . I need to check if given pattern actually matches the data. How to approach this? awk, date? EDIT: More info: The user enters the strftime format, let's say on input. Then he enters a file which should contain those dates. I need to make sure, that those data are valid (he didn't make a mistake). So I need to check the rows in the input file and see, if

问题 I have a huge data set with say 15 - 20 GB and it is a tab delimited file. While I can either do it in Python or in SQL, It would be easier and simple to have it done in Shell script to avoid moving the csv files Say, For example, taking a pipe delimited file input: ---------------------------------------- Col1 | Col2 | Col3 | Col4 | Col5 | Col6 ---------------------------------------- A | H1 | 123 | abcd | a1 | b1 ---------------------------------------- B | H1 | 124 | abcd | a2 | b1 -------

问题 ok, straight to the point, here is the codes, I formatted the codes a little to make it easy to read: awk '{ t=$0 ; $0=t ; $0=// ; print "$0=// ; value of $0 is ",$0 $0=t ; $0=/./ ; print "$0=/./ ; value of $0 is ",$0 $0=t ; $0=/*/ ; print "$0=/*/ ; value of $0 is ",$0 $0=t ; $0=/**/ ; print "$0=/**/ ; value of $0 is ",$0 $0=t ; $0=/[0-9]/ ; print "$0=/[0-9]/ ; value of $0 is ",$0 $0=t ; $0=/[a-z]/ ; print "$0=/[a-z]/ ; value of $0 is ",$0 $0=t ; $0=/[0-9][a-z]/ ; print "$0=/[0-9][a-z]/ ;

问题 awk -i inplace ' BEGIN {FS=" "} BEGINFILE {changed=0} { print;if ($1 == "namespace" && !changed) {print "foo";changed=1} } ' * Is there a more elegant way to do this? Some built-in construct I missed? I am running GNU Awk 4.1.0 (and I am superb glad for -i inplace). 回答1: awk -i inplace '$1=="namespace" && !seen[ARGIND]++ {$0=$0 ORS "foo"} 1' * FS=" " is the default, no need to specify it explicitly. 回答2: You could say: ... -F' ' '$1 == "namespace" && !a {$0=$0 RS "foo";a=1}1' file or even: ..

问题 I am trying to insert a line after the Pattern using gawk . Let's say, file aa contains 11 22 33 11 22 33 I'm using gawk to insert 222 only after first 22, i.e. after insertion, my aa file would contain: 11 22 222 33 11 22 33 But, if I use: gawk -v nm=222 '/22/ {if (done++ == 0) print;print nm;next}1' aa The file aa contains: 11 22 222 33 11 222 33 (I don't want second replacement of 22 by 222 and like to retain 22 as-is, and no more insertion, i,e,. insert 222 only once after first 22.

问题 Related question: https://stackoverflow.com/posts/18164848 The input file input.txt is a tab delimited unicode txt with a A e f m b B g h c C i j b B k l I want to match by the first and second column and merge. So I want to get output.txt with a A e f m b B g h k l c C i j The code has to detect the maximum number of columns in the input. Since it is 5 in this example, "k l" were put from 6th column. Actually I almost managed to do this using Matlab when they are all numbers. But oh, when

问题 the w command produces something like this: 01:19:02 up 53 days, 10:44, 15 users, load average: 0.00, 0.02, 0.00 USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT higrheht pts/5 c-13-76-207-161. 23:21 2:05 0.07s 0.07s -bash sgergrgr pts/6 c-97-164-31-14.h 00:54 2.00s 0.04s 0.04s -bash jwegrgrng pts/14 c-23-71-12-251.h 22:48 8:03 0.07s 0.06s vim s2 hiqrefan pts/18 c-13-31-206-169. 23:19 0.00s 0.01s 0.01s -bash hqeffran pts/19 c-19-71-206-169. 23:19 1:58m 0.02s 0.02s -bash aqrgri pts/20 c-84-6-212-27.hs

问题 Say I have come up with a regex matching a piece of data; the regex contains 2 sed groups (sub-expressions enclosed in ( and ) ). Also say that this regex is duplicated 9 times to match a whole line. The problem I am facing is how to delete (in an elegant way) every second match against the regex. 回答1: Let's say you have the following string and want to remove the occurrences of bar : foo bar foo bar foo bar You can use the following sed command, note the option g which makes the substitution

问题 Question so I have the following line of code: if (sum[msg,h]/summsg[msg,h] != 0) printf ("%9.2f\n",sum[msg,h]/summsg[msg,h]) msg is a message array holds 10 distinct values hr holds all hours present in a log file. the sum[] array is addind together values of a field ( sum[$5,$3] += $11 ) and the summsg[] array is counting the number of lines ( summsg[$5,$3]++ ) This is retuning a fatal: division by zero attempted error, but I thorght that awk would evaluate the sum[msg,h]/summsg[msg,h] != 0

问题 I have several large log files that include lines in the following format: /resource/text_(moretext Now these need to be closed with a ")", but the file is way too large to do this manually. Unfortunately the text within the lines can be anything. So I think I need some expression that is able to find all lines that have "(" and no ")". Then these lines have to be replaced with the exact same content but with ")" added to the end. So it should look like this: Before: /resource/text_(moretext