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How to give a “Dashed Border” in flutter?

匿名 (未验证) 提交于 2019-12-03 01:34:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I try to give dashed border in flutter but there is no option for dashed border in flutter. so any another way to create dashed border in futter. new Container ( decoration : new BoxDecoration ( border : Border ( left : BorderSide ( color : Color ( 0XFFFF6D64 ), width : 2.0 ))), height : 20.0 , margin : const EdgeInsets . only ( left : 35.0 ), child : new Row ( crossAxisAlignment : CrossAxisAlignment . start , children : < Widget >[ new DecoratedBox ( decoration : new BoxDecoration ( border : Border ( left : BorderSide ( color :

CSS-only Acrylic Material from Fluent Design System

匿名 (未验证) 提交于 2019-12-03 01:27:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: With the advent of Microsoft's Fluent Design System and the propagation of the new Acrylic Material around the Windows ecosystem, I thought it would be great to use it in some Web layouts. Acoording to the spec , the composition of an acrylic layer is: So I went to try a CSS-only approach inspired by the layers in that picture, this way: body { margin: 0; font: 1em/1.4 Sans-serif; background: url("http://www.wallpapers-web.com/data/out/191/5484624-sunset-wallpapers.jpg") center center; background-size: 100vw auto; } main { display: flex;

Delete old files

匿名 (未验证) 提交于 2019-12-03 01:12:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I need help creating a Google Drive script that will automatically delete all old files except the 24 most recent files. My network drive every hour sends to Google Drive packed 7z of a database file named: DATABASENAME_01.09.2017_07.bak.7z and in general the format: DATABASENAME_DD.MM.RRRR_HH.bak.7z The files on Google Drive are copied directly (I do not have any folders). I would like the files to be deleted instead of being moved to the trash. It's about releasing space. I wanted to employ other solutions described on Stackoverflow, but

Passing a matplotlib figure to HTML (flask)

匿名 (未验证) 提交于 2019-12-03 01:12:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I am using matplotlib to render some figure in a web app. I've used fig.savefig() before when I'm just running scripts. However, I need a function to return an actual ".png" image so that I can call it with my HTML. Some more (possibly unnecessary) info: I am using Python Flask. I figure I could use fig.savefig() and just stick the figure in my static folder and then call it from my HTML, but I'd rather not do that every time. It would be optimal if I could just create the figure, make an image out of it, return that image, and

Is it possible to run clang with llc flags

匿名 (未验证) 提交于 2019-12-03 00:59:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Is there a way to run the clang and add llc flags ? I want to use "-print-after-all", "-print-before-all", "-debug-only" ... without having to use the .bc file in between. 回答1: Additional arguments can be passed to LLVM's option parser with -mllvm . For your scenario this would look something like this: clang [...] -mllvm -print-after-all 文章来源: Is it possible to run clang with llc flags

Flask学习笔记(11)――使用Flask-SocketIO完成服务端和客户端的双向通信

匿名 (未验证) 提交于 2019-12-03 00:18:01
介绍: flask-socketio模块实际上是封装了flask对websocket的支持,websocket在连接建立阶段是通过HTTP的握手方式进行的,这可以看做是为了兼容浏览器或者使用一些现成的功能来实现,这样一种捷径。当连接建立之后,客户端和服务端之间就不再进行HTTP通信了,所有信息交互都由websocket接管。Flask-SocketIO使Flask应用程序可以访问客户端和服务器之间的低延迟双向通信,使客户端建立与服务器的永久连接。 适用的场景: 后台产生新的数据,需要在前台页面马上展示出来,例如数据监控、统计图实时变化更新等。 当然,我们可以使用ajax来完成,通过ajax使得前台定时去后台索要数据,但如果消息频繁,ajax需要不断的建立和释放连接,效果明显不如后端直接推送数据到前台更加合适。 Flask-SocketIO的使用 首先安装依赖: pip install flask-socketio 一个简单的示例 (对Flask代码加了一层包装): from flask import Flask, render_template from flask_socketio import SocketIO app = Flask(__name__) app.config['SECRET_KEY'] = 'secret!' socketio = SocketIO(app)

CCF20183-3-URL映射

匿名 (未验证) 提交于 2019-12-03 00:18:01
3.2.1 URL Django Ruby on Rails (web frameworks) HTTP URL URL URL URL URL URL URL URL / - _ . /person/123/ URL /person/123? ? /case/ /CAse/ URL URL URL 3 <str> abcde0123 <int> 01234 <path> abcd/0123/ 3 <str> <int> <path> URL n m URL URL 2 n +1 URL i +1 p i r i p i 琛ㄧず URL r i URL n +2 n + m +1 URL n +1+ i q i URL m i q i p j r j 404 5 4 /articles/2003/ special_case_2003 /articles/<int>/ year_archive /articles/<int>/<int>/ month_archive /articles/<int>/<int>/<str>/ article_detail /static/<path> static_serve /articles/2004/ /articles/1985/09/aloha/ /articles/hello/ /static/js/jquery.js year

CDH6.1集成FLINK1.9.0(CDH上安装FLINK)

匿名 (未验证) 提交于 2019-12-03 00:11:01
导读 CDH除了能够管理自生所提供的一些大数据相关服务外,还允许将第三方服务添加到CDH集群(托管在CDH上)。你需要做的就是按照一定的规则流程制作相关程序包,最后发布到CDH上。虽然过程并不困难,但是手动操作尤其是一些关键配置容易出错,往往导致最终服务无法正常在CDH上安装运行。 本文就是指导大家如何打包自己的服务,发布到CDH上,并且由CDH控制服务的运行、监控服务的基本运行状态。 相关介绍 名词介绍 (1)parcel : 以".parcel"结尾的压缩文件。parcel包内共两个目录,其中lib包含了服务组件,meta包含一个重要的描述性文件parcel.json,这个文件记录了服务的信息,如版本、所属用户、适用的CDH平台版本等。 命名规则必须如下 : 文件名称格式为三段,第一段是包名,第二段是版本号,第三段是运行平台。 例如:FLINK-1.9.0-bin-scala_2.12-el7.parcel 包名 :FLINK 版本号 :1.9.0-bin-scala_2.12 运行环境 :el7 el6是代表centos6系统,centos7则用el7表示 ps : parcel必须包置于/opt/cloudera/parcel-repo/目录下才可以被CDH发布程序时识别到。 (2)csd :csd文件是一个jar包,它记录了服务在CDH上的管理规则里面包含三个文件目录

线段树优化dp(elect选择)

匿名 (未验证) 提交于 2019-12-02 23:49:02
好几天以前的考试题,现在才想起来调。。 题意 暴力:O(n*m*m*T) 优化 :对于将要选的一行格子,将其上一行格子能够覆盖的范围处理出来,然后选这一行时,希望较快的得到在这个格子可以选的范围里面,权值最小的一格 于是对每一行用线段树维护最小值,到了下一行就把线段树清空,重新modify #include<bits/stdc++.h> using namespace std; #define mid ((l+r)>>1) #define N 105 #define M 5005 #define inf 0x7f7f7f int a[N][M],dp[N][M],minn[M*4],fl[M*4],l[N][M],r[N][M]; void update(int s) { minn[s]=min(minn[s<<1],minn[s<<1|1]); } void pushdown(int s) { if(fl[s]==inf) return ; minn[s<<1]=min(minn[s<<1],fl[s]); fl[s<<1]=min(fl[s<<1],fl[s]); minn[s<<1|1]=min(minn[s<<1|1],fl[s]); fl[s<<1|1]=min(fl[s<<1|1],fl[s]); fl[s]=inf; } void build(int s,int l

python--几个重要内置函数(zip,fliter,map,sorted)

匿名 (未验证) 提交于 2019-12-02 22:51:30
# # zip 拉链方法 # l = [1,2,3] # l2 = ['a','b','c'] # l3 = ('*','**',[1,2]) # d = {'k1':1,'k2':2,'k3':3} # for i in zip(l,l2,l3,d): # print(i) # # # filter # def is_odd(x): # return x % 2 == 1 # # def is_str(s): # if type(s) != int: # return s and str(s).strip() # # ret = filter(is_odd, [1, 4, 6, 7, 9, 12, 17]) # # ret = filter(is_str, [1,'hello', 6, 7,'world',12,17]) # ret = filter(is_str, [1,'hello','',' ',None,[],6,7,'world',12,17]) # print(ret) # for i in ret: # print(i) # [i for i in[1, 4, 6, 7, 9, 12, 17] if i % 2 == 1] """ 用filter过滤出1~100中平方根是整数的数, """ # import math # def is_sqr(x): #