fasterxml

RestTemplate入门

由 醉酒当歌 提交于 2019-12-17 10:22:59
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> RestTemplate入门  本篇主要讲解RestTemplate的基本使用，它是Spring提供的用来访问Rest服务的客户端，RestTmplate提供了很多便捷的方法，可以大大提供开发效率，本篇只涉及基本使用，内部原理后续再展开  1.RestTemplate简述  RestTemplate是Spring提供的用于发送HTTP请求的客户端工具，它遵循Restful原则，RestTemplate默认依赖JDK的Http连接工具HttpUrlConnection,你也可以替换不同的源，比如OkHttp、Apache HttpComponents 等等。。  2.HttpMessageConverter  在说RestTemplate之前,先介绍HttpMessageConverter，RestTemplate默认使用的转化HttpMessageConverter去将Http消息转换成POJO 或者 POJO转化成Http消息。在创建RestTemplate的时候会默认添加一组HttpMessageConveter的实现。  HttpMessageConverter源码： public interface HttpMessageConverter<T> { //指示此转换器是否可以读取给定的类。

kotlin使用spring data redis（二）

由 人盡茶涼 提交于 2019-12-13 21:48:19
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 自定义序列化器 1.标准json序列化器，时间类型禁用时间戳 import com.fasterxml.jackson.core.JsonProcessingException import com.fasterxml.jackson.databind.ObjectMapper import com.fasterxml.jackson.databind.SerializationFeature import com.fasterxml.jackson.datatype.jdk8.Jdk8Module import com.fasterxml.jackson.datatype.jsr310.JavaTimeModule import com.fasterxml.jackson.module.kotlin.jacksonObjectMapper import com.fasterxml.jackson.module.kotlin.readValue import org.springframework.data.redis.serializer.RedisSerializer import org.springframework.data.redis.serializer

How to add an ObjectNode into another ObjectNode as a child using Jackson?

由 霸气de小男生 提交于 2019-12-13 17:18:06
问题 I have the below ObjectNode. handlerObjectNode -> {"Info":{"Brand":{"BrandName":"TOP OF THE WORLD"}}} I have another ObjectNode in the following format. fieldObjects -> {"Description":"REGULAR BR"} How can I create the below ObjectNode from the above two? { "Info": { "Brand": { "BrandName": "TOP OF THE WORLD" } "Description": "REGULAR BR" } } I tried the below code. handlerObjectNode.setAll(fieldObjects); But it results in the following ObjectNode. { "Info": { "Brand": { "BrandName": "TOP OF

How to implement customized serialization feature in fasterxml

由 醉酒当歌 提交于 2019-12-13 00:42:21
问题 My JSON: { "name": "asdf", "age": "15", "address": { "street": "asdf" } } If street is null, with JsonSerialize.Inclusion.NON_NULL , I can get.. { "name": "asdf", "age": "15", "address": {} } But I want to get something like this.. (when address is not null, it is a new/empty object. But street is null.) { "name": "asdf", "age": "15" } I thought to have custom serialization feature like JsonSerialize.Inclusion.VALID_OBJECT . Adding isValid() method in the Address class then if that returns

Proguard causes Jackson error

由 走远了吗. 提交于 2019-12-12 14:07:33
问题 After enabling proguard rules I faced with the following So error come before sending anything to network. java.lang.RuntimeException: Unable to convert FormDocTankPermission to RequestBody caused by com.fasterxml.jackson.databind.exc.InvalidDefinitionException: No serializer found for class FormDocTankPermission and no properties discovered to create BeanSerializer (to avoid exception, disable SerializationFeature.FAIL_ON_EMPTY_BEANS) My class that I send as @Retrofit.Body look like

Error - JSON getting into infinite loop

由 痴心易碎 提交于 2019-12-12 02:53:09
问题 I am trying to display JSON data, for that i am using fasterxml jackson. I am able display JSON but the JSON is getting to infinite loop and in log file i am getting error as ERROR [org.apache.catalina.core.ContainerBase.[jboss.web].[default-host].[/EAD].[spring]] (http--127.0.0.1-8080-1) Servlet.service() for servlet spring threw exception: java.lang.ClassNotFoundException: com.fasterxml.jackson.databind.JsonMappingException$Reference from [Module "deployment.EAD.war:main" from Service

Java: FasterXML / jackson deserialize array without keys

由 生来就可爱ヽ(ⅴ＜●) 提交于 2019-12-12 02:34:06
问题 Is there a way how to deserialize JSON array {["a", "b", 1]} into following Java class class MyObject { private String firstItem; private String secondItem; private int thirdItem; } ussing FasterXml jackson-databinding? I only found answers where there are key: value items in the array. 回答1: Firstly {["a", "b", 1]} is not a Valid Json Array (or JSON) .... JSON Array would look like this ["a", "b", 1] Also you could deserialize the Json Array into a Java Object by writing a Custom Deserializer

Is there a way to modify a POJO field and return the POJO

由 冷暖自知 提交于 2019-12-11 19:53:40
问题 Is there a way to modify the field of POJO with new property(like using MixIns or @JSONProperty ) and get the modified POJO back ? (A way to add/modify field of a POJO dynamically ?) Like I have a class class PojoA<T>{ private T data;//field to be modified as NewData } So, I tried with MixIns like public interface PojoMixIn<T> { @JsonProperty("NewData") T getData(); } Now to get the modified field, I use ObjectMapper mapper.addMixInAnnotations(PojoA.class,PojoMixIn.class); mapper

Serializing nested org.json.JSONObject using gson.toJson adding into “map” key

由 旧城冷巷雨未停 提交于 2019-12-11 16:59:33
问题 In my code, I need to add an org.json.JSONObject to another object which is serialized using gson.toJson . However, when this object is serialized, the values in the JSONObject are nested into a map key by gson itself. For example, public class New { private static final Gson gson = new GsonBuilder().disableHtmlEscaping().create(); public static void something(User user) throws Exception { try { ObjectWriter ow = new ObjectMapper().writer(); String json = ow.writeValueAsString(user);

What is the relation between fasterxml(jackson-dataformat-xml) and Woodstox?

由 本秂侑毒 提交于 2019-12-11 14:00:02
问题 I am sorry if my question is invalid but wanted to know what's the relation between fasterxml(jackson-dataformat-xml) and Woodstox. The documentation(https://github.com/FasterXML/jackson-dataformat-xml) suggests me to add maven dependency of Woodstox while using jackson-dataformat-xml. 回答1: The jackson-dataformat-xml project does not like the Stax implementation provided by the JDK (at least not the one provided by JDK 8). https://github.com/FasterXML/jackson-dataformat-xml/issues/32
订阅 fasterxml