django-permissions

Is there a way to do row level permissions in django? I thought there wasn't but just noticed this in the docs: Permissions can be set not only per type of object, but also per specific object instance. By using the has_add_permission(), has_change_permission() and has_delete_permission() methods provided by the ModelAdmin class, it is possible to customize permissions for different object instances of the same type. https://docs.djangoproject.com/en/dev/topics/auth/ But i don't see any documentation on how to actually implement per instance permissions For an application i'm building i want

I am using custom permissions in my Django models like this: class T21Turma(models.Model): class Meta: permissions = (("can_view_boletim", "Can view boletim"), ("can_view_mensalidades", "Can view mensalidades"),) The problem is that when I add a permission to the list it doesn't get added to the auth_permission table when I run syncdb. What am I doing wrong. If it makes any difference I am using south for database migrations. South does not track django.contrib.auth permissions. See ticket #211 for more information. One of the comments on the ticket suggests that using the --all option on

When I create a user in Django, he has no permissions: In [7]: u = User.objects.create(username='aoeu') In [12]: u.user_permissions.all() Out[12]: [] I want some permissions to be set by default (say, 'api.add_item'), and I use Django Guardian . Is this possible to do in a declarative way, eg. without writing a post_save signal? No, it is not possible. Check django.contrib.auth code to ensure 来源： https://stackoverflow.com/questions/12312931/how-do-i-define-default-permissions-for-users-in-django-guardian

I want to add a permission under auth_permission table. When I insert another permission manually, I need to insert a content_type_id also. This is referenced to content_type table. I dont know what it does. I want to remove set of HTML lines if user doesn;t have that permission. What's the importance of content_type_id ? "content_type_id" is the name of the field as determined by Django. The field is a foreign key relation ship to an instance of ContentType. The importance of this field is that it designates the object to which the permission applies (from the django source code 1.7.11):

I've been searching Google and Stackoverflow for the last 3 days now and couldn't find anything similar. I'd like to extend or use the django groups and permissions. Let's say we got some Projects with different Teams and Users. class Project(models.Model): owner = models.ForeignKey(User) name = models.CharField(max_length=100) class Team(models.Model): project = models.ForeignKey(Project) members = models.ManyToManyField(User) name = models.CharField(max_length=100) permission = models.ManyToManyField(Permission) Now - everything's fine. Now what I want is to extend the existing Auth.Group

I'd like to be able to give some existing Users a custom permission which I will require for accessing a view. I think I need to add the new permission to the Postgres table auth_permission, but I suspect there is a higher-level way to do this. Also there is a column in auth_permission for content_type and I don't know what its value should be. What is the right way to do this? sheats Have a look at how to create custom permissions in the docs. class USCitizen(models.Model): # ... class Meta: permissions = ( ("can_drive", "Can drive"), ("can_vote", "Can vote in elections"), ("can_drink", "Can

I've found 3 row-level permission solutions for Django 1.2+ django-object-permissions django-guardian django-authority Could someone tell if there is any recommended more than the others, what are their main differences, etc.? I'll start this by saying we use none of these for object level permission - we use our own custom method and I really wish we hadn't. If you can avoid object level permissions at all, do so, they are a pain to organise. This is how I evaluate the 3 apps you've mentioned. Active Development: django-guardian (1 week ago) django-object-permissions (1 year ago) django