django-admin

问题 Is there a way to change the url to open the admin site in django? I don't want to use the default /admin url. I am new to django so please try giving a bit more detailed information. 回答1: In urls.py, change the line that reads: (r'^admin/(.*)', admin.site.root), to something like: (r'^new_admin/(.*)', admin.site.root), so now instead of http://example.com/admin you'd use http://example.com/new_admin 回答2: Sure, the file urls.py in the root of your project maps URLs to handlers. Just change

问题 Let's imagine we have those Django models: class Band(models.Model): name = models.CharField(max_length=256, default="Eagles of Death Metal") class Song(models.Model): band = models.ForeignKey(Band) When using the admin to manage those models, the band field is associated to a Widget rendered by Django as a select html element. Django's admin also adds a green plus icon next to the select , clicking it opens a pop-up window where the user is presented with the Form to add a new band. When

问题 I use django-registrations and while I add this code in my admin.py from django.contrib import admin from customer.models import Customer from .models import UserProfile from django.contrib.auth.admin import UserAdmin from django.contrib.auth import get_user_model class UserProfileInline(admin.StackedInline): model = UserProfile can_delete = False class UserProfileAdmin(UserAdmin): inlines=(UserProfileInline, ) admin.site.unregister(get_user_model()) admin.site.register(get_user_model(),

问题 I have a model Item class Item(models.Model): id = models.IntegerField(primary_key=True) title = models.CharField(max_length=140, blank=True) description = models.TextField(blank=True) price = models.DecimalField(max_digits=12, decimal_places=2, blank=True, null=True) and my model admin class ItemAdmin(admin.ModelAdmin): list_display = ['item_view', 'description', 'item_price', 'seller_view', 'added_on'] actions = ['add_to_staff_picks'] search_fields = ('description', 'title') def item_view

问题 In a Django project, I have a custom user model that adds one extra field: class User(AbstractUser): company = models.ForeignKey(Company, null=True, blank=True) This model is defined in my app, say MyApp.models . How can I get the new User model to show up under "Authentication and Authorization" as the original django.contrib.auth model? 回答1: class User(AbstractUser): class Meta: app_label = 'auth' This can solve your problem but may cause some errors when you migrate your app. The other

问题 In a Django project, I have a custom user model that adds one extra field: class User(AbstractUser): company = models.ForeignKey(Company, null=True, blank=True) This model is defined in my app, say MyApp.models . How can I get the new User model to show up under "Authentication and Authorization" as the original django.contrib.auth model? 回答1: class User(AbstractUser): class Meta: app_label = 'auth' This can solve your problem but may cause some errors when you migrate your app. The other

问题 Given a model named MainModel and a RelatedModel , where the later has a ForeignKey field to MainModel : class MainModel(models.Model): name = models.CharField(max_length=50) type = models.BooleanField() class RelatedModel1(models.Model): main = models.ForeingKey(MainModel): name = models.CharField(max_length=50) class RelatedModel2(models.Model): main = models.ForeingKey(MainModel): name = models.CharField(max_length=50) and the corresponding ModelAdmin classes: class

问题 Given a model named MainModel and a RelatedModel , where the later has a ForeignKey field to MainModel : class MainModel(models.Model): name = models.CharField(max_length=50) type = models.BooleanField() class RelatedModel1(models.Model): main = models.ForeingKey(MainModel): name = models.CharField(max_length=50) class RelatedModel2(models.Model): main = models.ForeingKey(MainModel): name = models.CharField(max_length=50) and the corresponding ModelAdmin classes: class

问题 I am currently working on the Django==3.1.3 version but would like to change the interface like that of the django==3.1 Admin view. The current view looks something like this: I would like to remove the red part and keep the remaining part of the page. 来源： https://stackoverflow.com/questions/65020639/how-to-change-the-django-3-1-3-admin-view

问题 I am currently working on the Django==3.1.3 version but would like to change the interface like that of the django==3.1 Admin view. The current view looks something like this: I would like to remove the red part and keep the remaining part of the page. 来源： https://stackoverflow.com/questions/65020639/how-to-change-the-django-3-1-3-admin-view