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how to call javascript function from android using phonegap plugin

由 随声附和 提交于 2019-12-29 09:20:10
问题 This is my index.html <!DOCTYPE HTML> <html> <head> <title>PhoneGap</title> <script type="text/javascript" charset="utf-8" src="cordova-1.7.0rc1.js"></script> <script type="text/javascript" charset="utf-8"> function call(){ console.log("ANDROID"); } </script> </head> <body > </body> </html> This is my receiver class package com.example.jsfrmjv; import org.apache.cordova.DroidGap; import android.content.BroadcastReceiver; import android.content.Context; import android.content.Intent; import

How to call a Managed DLL File in C#?

由 守給你的承諾、 提交于 2019-12-29 07:17:48
问题 I am making a scripting language but I have a serious problem. I need to make it so you can call .NET DLLs in the language but I have found no way to do this in C#. Does any one know how can I load and call a .NET dll programmatically? (I can not just Add reference so don't say that) 回答1: Here's how I did it: Assembly assembly = Assembly.LoadFrom(assemblyName); System.Type type = assembly.GetType(typeName); Object o = Activator.CreateInstance(type); IYourType yourObj = (o as IYourType); where

make a call in iphone from my application

由 南楼画角 提交于 2019-12-29 06:30:51
问题 how can i make call from my application to particular no. Give me some logic or code for performing this task... 回答1: Use UIApplication's openURL: method: [[UIApplication sharedApplication] openURL: [NSURL URLWithString:[NSString stringWithFormat:@"tel:%@",phoneNumber]]]; 来源： https://stackoverflow.com/questions/3385901/make-a-call-in-iphone-from-my-application

“<method> takes no arguments (1 given)” but I gave none

由 怎甘沉沦 提交于 2019-12-29 04:30:11
问题 I am new to Python and I have written this simple script: #!/usr/bin/python3 import sys class Hello: def printHello(): print('Hello!') def main(): helloObject = Hello() helloObject.printHello() # Here is the error if __name__ == '__main__': main() When I run it ( ./hello.py ) I get the following error message: Traceback (most recent call last): File "./hello.py", line 13, in <module> main() File "./hello.py", line 10, in main helloObject.printHello() TypeError: printHello() takes no arguments

How can I call a javascript constructor using call or apply? [duplicate]

由 余生长醉 提交于 2019-12-28 07:36:26
问题 This question already has answers here : Use of .apply() with 'new' operator. Is this possible? (36 answers) Closed 4 years ago . How could I generalise the function below to take N arguments? (Using call or apply?) Is there a programmatic way to apply arguments to 'new'? I don't want the constructor to be treated like a plain function. /** * This higher level function takes a constructor and arguments * and returns a function, which when called will return the * lazily constructed value. * *

How can I call a javascript constructor using call or apply? [duplicate]

由 一世执手 提交于 2019-12-28 07:36:11
问题 This question already has answers here : Use of .apply() with 'new' operator. Is this possible? (36 answers) Closed 4 years ago . How could I generalise the function below to take N arguments? (Using call or apply?) Is there a programmatic way to apply arguments to 'new'? I don't want the constructor to be treated like a plain function. /** * This higher level function takes a constructor and arguments * and returns a function, which when called will return the * lazily constructed value. * *

Applying a Function to Null in Javascript

由 旧时模样 提交于 2019-12-28 04:04:28
问题 Why does the following work: function sum(a,b) { return a + b; } var result = sum.call(null,3,4); // 7 Why is result defined? I am invoking sum as a method of null. But null is not an object and cannot have properties! What is going on? 回答1: The first argument for Function.prototype.call is the context , which defines the this value for the execution context of the invoked function, nothing else. So basically, you're saying that this is referring to null (at least, in ES5 strict mode), but

How to call a private method from outside a java class

由 倖福魔咒の 提交于 2019-12-28 02:37:04
问题 I have a Dummy class that has a private method called sayHello . I want to call sayHello from outside Dummy . I think it should be possible with reflection but I get an IllegalAccessException . Any ideas??? 回答1: use setAccessible(true) on your Method object before using its invoke method. import java.lang.reflect.*; class Dummy{ private void foo(){ System.out.println("hello foo()"); } } class Test{ public static void main(String[] args) throws Exception { Dummy d = new Dummy(); Method m =

How to execute a function asynchronously every 60 seconds in Python?

由 浪尽此生 提交于 2019-12-27 19:12:32
问题 I want to execute a function every 60 seconds on Python but I don't want to be blocked meanwhile. How can I do it asynchronously? import threading import time def f(): print("hello world") threading.Timer(3, f).start() if __name__ == '__main__': f() time.sleep(20) With this code, the function f is executed every 3 seconds within the 20 seconds time.time. At the end it gives an error and I think that it is because the threading.timer has not been canceled. How can I cancel it? Thanks in

The response from the retrofit call is too slow and it returns a null list

由 最后都变了- 提交于 2019-12-27 01:19:18
问题 Getting response as null in onResponse(). How to improve time duration for response? public class RequestClass { private static final String TAG = RequestClass.class.getSimpleName(); private final static String API_KEY = "apikey"; static ApiInterface apiService = ApiClient.getClient().create(ApiInterface.class); static public List<Movie> getTopMovies(String page) { final List<Movie> lowDetailMovies = new ArrayList<Movie>(); Call<MoviesResponse> call = apiService.getTopRatedMovies(API_KEY,
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