cakephp-1.2

问题 Is there an easy way to share login information between two cakephp apps on the same domain? Basically, MainApp has a full fledged user management suite, and I just want SecondaryApp to know if a visitor is logged in or not. 回答1: Make sure both applications are configured to handle the session the same way. In other words, we want both apps to read from the same cookie and we need both apps to look in the same location for that cookie. //app\config\core.php for both apps Configure::write(

问题 I'm using CakePHP 1.2 with Auth and ACL components. In my user register action, the password is coming in unhashed. Specifically, this expression: if ($this->data['User']['password'] != $this->Auth->password($this->data['User']['confirm_password'])) This is evaluating to true, even when I submit identical values for password and confirm_password . I know that password is unhashed because when I remove the call to Auth->password , the expression evaluates to false. I expected the Auth module

问题 CakePHP Version 1.2.5 I would like a single user to have multiple email addresses. I would like a single user to have a single password. I would like users to log in using any of their multiple email addresses and their single password. I have created a users table with an id and a password field. I have created a user_email_addresses table with an id field a user_id field and an email_address field. Question: How do I modify the auth component minimally to look for the "username" in this

问题 How to Limit the paginate in cakephp ? Assume that i have 400 records. I need to get only 25 records from 50th record to 75th record and need to display 5 records per page. How i can do this in paginate ? Sample Code: $this->paginate = array( 'contain'=>array('User'), 'recursive' => 2, 'order' => array('Profile.winning' => 'DESC'), 'limit' =>5 ); 回答1: You can set conditions for the pagination. function listRecords() { $this->paginate = array( 'conditions' => array('Model.id >=' => 50, 'Model

问题 I'm using cakephp 1.2, and I have a search form which has also this menu: Classificazione  <select style="margin-top: 5px;" name="classificazione"> <option value="art0"></option> <option value="C">Articoli</option> <option value="D">Documentazione</option> <option value="A">Libri</option> <option value="G">Materiali</option> <option value="B">Riviste</option> <default value="A"> </select><br /> In the next page I want to set the default value of this menu with what the user has chosen before.

问题 I CakePHP (cake_1.2.2.8120) and EasyPHP (3.0) installed on Windows Vista Ultimate. I followed the "baking" tutorials online, successfully set the database connection with the "cake bake" command from the CLI. I baked the controller for my "Users" table using the "php cake.php bake controller Users" command - worked fine. However, when I tried baking the view similarly, I got this message: Fatal error: Call to undefined function mysql_connect() in C:\Web\EasyPHP \www\cake\cake\libs\model

问题 How can I Measure the Page Execution Time in CakePHP 2.1? In 1.3 it was rendered in the code when in debug mode. 回答1: You could use DebugKit Plugin to find out execution time. Or you can edit index.php in app/ and add: // top of file $starTime = microtime(true); // bottom of file echo '<!-- Exec time: ', microtime(true) - $startTime, ' -->'; That time will be in microseconds so you could convert it to ms if you want, but DebugKit gives you a lot more information. 回答2: Note that the time

问题 I would like to log PHP errors on a CakePHP site that has debug = 0. However, even if I turn on the error log, like this: error_reporting = E_ALL & ~E_NOTICE & ~E_DEPRECATED log_errors = On it doesn't log errors. The problem is that even for a parse error that should cause the CakePHP environment to not load completely (I think), it still blocks the error from being logged. If I set debug to 3, it logs to the file without issue. I am using CakePHP 1.2. I know this is apparently made easier in

问题 I am having trouble getting the Auth component do the redirects I want in a CakePHP 1.2.6 app. I have a login form that appears on all pages and I want to keep the user on the page he logs in on. For example, if he is viewing another user's profile, I want to keep him there after logging in, not redirect him to the $this->Auth->loginRedirect action. Also, another thing about my app is that I have no "authenticated access only" pages, every page is accessible to everyone, but if you're logged

问题 I am trying to set up my ACL with the following action in my UsersController: class UsersController extends AppController { var $name = 'Users'; var $helpers = array('Html', 'Form'); function beforeFilter() { parent::beforeFilter(); $this->Auth->allow('*'); } function install() { $group =& $this->User->Group; //Allow admins to everything $group->id = 1; $this->Acl->allow($group, 'controllers'); //allow users $group->id = 2; $this->Acl->deny($group, 'controllers'); $this->Acl->allow($group,