bisection

问题 I've had problems with this before but now it's somehow working. Now I've following problem. I need to bind values into member-function before I call boost::bisect with the same function. I found pretty good tutorial and I've followed it but it seems that I'm still doing something wrong. At first I created test class where I got following working: std::pair<double, double> result = bisect(&Func, 0.0, 1.0, TerminationCondition()); double root = (result.first + result.second) / 2; After that I

问题 I have a code for finding the bisection (and it finally works!), but I need to include 3 more things: output- Root History a vector containing the sequence of midpoints obtained by the algorithm output- the absolute value of the function f(x) at r, i.e., fRoot = f(r) input- max iterations function [R, E] = myBisection(f, a, b, tol) m = (a + b)/2; R = m; E = abs(f(m)); while E(end) > tol if sign(f(a)) == sign(f(m)) a = m; else b = m; end m = (a + b)/2; R = [R, m]; E = [E, abs(f(m))]; end how

问题 I am trying to find the best rate of savings to achieve a down payment on a $1million house in 36 months. savings need to be within 100$ of required down payment. downpayment is 25% of total cost. I have to search for an integer between 0 and 10000 (using integer division), and then convert it to a decimal percentage (using float division) to use when we are calculating the current_savings​ after 36 months. This is my code which is not working (I am really new to programming) annual_salary =

问题 How many recursions are made before every single root is found? Also, which ones are the roots? Here's my code: e=0.000001; f1=@(x) 14.*x.*exp(x-2)-12.*exp(x-2)-7.*x.^3+20.*x.^2-26.*x+12; a=0; c=3; while abs(c-a)>e b=(c+a)/2; if f1(a)*f1(b)<0 c=b; else a=b; end disp(b); end 回答1: Bisection works by taking endpoints of some initial interval [a,b] and finding which half of the interval must contain the root (it evaluates the midpoint, and identifies which half has the sign change). Then

问题 Is there a library function that performs binary search on a list/tuple and return the position of the item if found and 'False' (-1, None, etc.) if not? I found the functions bisect_left/right in the bisect module, but they still return a position even if the item is not in the list. That's perfectly fine for their intended usage, but I just want to know if an item is in the list or not (don't want to insert anything). I thought of using bisect_left and then checking if the item at that

问题 How do I go about making a for-loop with a range 70000 and above? I'm doing a for-loop for an income tax and when income is above 70000 there is a tax of 30%. Would i do something like for income in range(income-70000) ? Well, at first i developed a code that didn't use a loop and it worked just fine, but then i was notified that i needed to incorporate a loop in my code. This is what i have, but it just doesn't make sense for me to use a for loop. Can someone help me? def tax(income): for

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 3 years ago . Could you explain where i'm going wrong with this code? I want to do a bisection search which takes input number and repeats bisection search until it finds the same number as input and prints out various statements. num =int( input("Please think of a number between 0 and 100!")) maximum = num minimum = 0

问题 This code gives pretty accurate result when deltanum = 0.0000000000001 but gets into an infinite loop when deltanum = 0.00000000000001 (adding another zero into deltanum ). It occurs only for non-perfect cubes, it works fine for perfect cubes like 1000. Why? I am new to programming, following OSSU. num = 100 high = num low = 0 icount = 0 cuberoot = (high + low)/2 #cuberoot of num deltanum = 0.00000000000001 while abs(cuberoot**3 - num)>=deltanum: icount+=1 print(icount) if cuberoot**3 > num:

问题 My code: monthlyInterestRate = annualInterestRate/12.0 low = balance/12 high = (balance*(1+monthlyInterestRate)**12)/12 guess = (low+high)/2 unpaidBalance = balance month = 1 while True: unpaidBalance= unpaidBalance-guess while month < 13: if unpaidBalance <= -0.1: low = guess month += 1 elif unpaidBalance >= 0.1: high = guess month += 1 else: break guess = (low + high)/2 print "Lowest Payment: " + str(round(guess, 2)) When I test it it gets stuck at the line "while month < 13:" Why does it

问题 I am trying to solve a quadratic equation using the bisection method. When trying to evaluate the roots I get this error: "no matching function for call". #include "assign4.h" #include <iostream> using namespace std; int main(int argc, char * argv[]){ solution s; double root; cout << "Enter interval endpoints: "; cin >> s.xLeft >> s.xRight; cout << "Enter tolerance: "; cin >> s.epsilon; root = s.bisect (s.xLeft, s.xRight, s.epsilon, s.f, s.error); if (!(s.error)) cout << "Root found at " <<