bisection

How to do the Bisection method in Python

由 半世苍凉 提交于 2019-12-09 12:14:32
问题 I want to make a Python program that will run a bisection method to determine the root of: f(x) = -26 + 85x - 91x2 +44x3 -8x4 + x5 The Bisection method is a numerical method for estimating the roots of a polynomial f(x). Are there any available pseudocode, algorithms or libraries I could use to tell me the answer? 回答1: Here's some code showing the basic technique: >>> def samesign(a, b): return a * b > 0 >>> def bisect(func, low, high): 'Find root of continuous function where f(low) and f

Calculate savings percentage for house down payment in 36 months

由 会有一股神秘感。 提交于 2019-12-08 04:26:09
问题 I'm currently learning Python on my own and this is the last problem in a problem set involving bisection search. I feel like I'm very close to solving this but not sure which part I did wrong. Problem: Write a program to calculate the savings percentage you need each month to afford the down payment in three years (36 months). Down payment: $250000 Semi-annual raise: 0.07 (7% raise every 6 months) Investment return: 0.04 (4%) Code: salary = 150000 semi_annual_raise = 0.07 investment_return =

calculate midpoint

由 ぃ、小莉子 提交于 2019-12-07 06:53:34
问题 Why in the bisection method it is better to compute the midpoint c between a and b with c = a + (b - a) / 2. instead of the simpler: c = (a + b) / 2. all variables are floating points. 回答1: it is to avoid any potential overflows / loss of precision in intermediate calculations. 来源： https://stackoverflow.com/questions/4064094/calculate-midpoint

Calculate savings percentage for house down payment in 36 months

由 …衆ロ難τιáo~ 提交于 2019-12-06 19:54:34
I'm currently learning Python on my own and this is the last problem in a problem set involving bisection search. I feel like I'm very close to solving this but not sure which part I did wrong. Problem: Write a program to calculate the savings percentage you need each month to afford the down payment in three years (36 months). Down payment: $250000 Semi-annual raise: 0.07 (7% raise every 6 months) Investment return: 0.04 (4%) Code: salary = 150000 semi_annual_raise = 0.07 investment_return = 0.04 down_payment = 250000 low = 0 high = 10000 percent_saved = int((low + high)/2) current_savings =

Calculate lowest monthly payment using bisection search in python

由 我怕爱的太早我们不能终老 提交于 2019-12-02 15:55:57
问题 I'm currently taking the MITx course on edx and I have a problem with one exercise. Can you please tell me why I get stuck in an infinite loop with this code? I guess the bisectional search loop isn't working properly but I don't really know why. Here's the code: balance = 5000 annualInterestRate = 0.18 low = balance/12 high = (balance * (1 + annualInterestRate / 12) ** 12) / 12 guess = (low + high)/2 def getBal(guess, balance, annualInterestRate): mon = 0 while mon < 12: mon += 1 ub =

Using boost::bind to bind member-function to boost::bisect?

由 穿精又带淫゛_ 提交于 2019-12-02 06:52:43
I've had problems with this before but now it's somehow working. Now I've following problem. I need to bind values into member-function before I call boost::bisect with the same function. I found pretty good tutorial and I've followed it but it seems that I'm still doing something wrong. At first I created test class where I got following working: std::pair<double, double> result = bisect(&Func, 0.0, 1.0, TerminationCondition()); double root = (result.first + result.second) / 2; After that I added binding "on the fly as I thought it could work" std::pair<double, double> result = bisect(boost:

Bisection method (Numerical analysis)

由 最后都变了- 提交于 2019-12-02 03:12:58
How many recursions are made before every single root is found? Also, which ones are the roots? Here's my code: e=0.000001; f1=@(x) 14.*x.*exp(x-2)-12.*exp(x-2)-7.*x.^3+20.*x.^2-26.*x+12; a=0; c=3; while abs(c-a)>e b=(c+a)/2; if f1(a)*f1(b)<0 c=b; else a=b; end disp(b); end Bisection works by taking endpoints of some initial interval [a,b] and finding which half of the interval must contain the root (it evaluates the midpoint, and identifies which half has the sign change). Then bisection repeats the process on the identified half. Bisection converges upon only one possible root, and if your

Using a recursive bisection algorithm to check if character is in string

由 荒凉一梦 提交于 2019-12-01 22:05:17
问题 I am currently doing the programming course over at edx and my instructions are as follows: Using the idea of bisection search, write a recursive algorithm that checks if a character is included within a string, as long as the string is in alphabetical order. My code(python 2.7) is here: def isitIn(char, aStr): m = aStr[len(aStr) // 2] if aStr == '' or len(aStr) == 1 or char == m: return False else: if char < m: return isitIn(char, aStr[:-1]) elif char > m: return isitIn(char, aStr[1:])

Using a recursive bisection algorithm to check if character is in string

由 自作多情 提交于 2019-12-01 20:03:32
I am currently doing the programming course over at edx and my instructions are as follows: Using the idea of bisection search, write a recursive algorithm that checks if a character is included within a string, as long as the string is in alphabetical order. My code(python 2.7) is here: def isitIn(char, aStr): m = aStr[len(aStr) // 2] if aStr == '' or len(aStr) == 1 or char == m: return False else: if char < m: return isitIn(char, aStr[:-1]) elif char > m: return isitIn(char, aStr[1:]) return isitIn(char, aStr) My explanation: I first start by finding the middle character of the string. If it

How to implement binary search in JavaScript

由 北战南征 提交于 2019-11-28 10:04:31
问题 https://www.khanacademy.org/computing/computer-science/algorithms/binary-search/p/challenge-binary-search I was following the pseudo code to implement algorithm on the link but don't know what's wrong with my code. Here is my code : /* Returns either the index of the location in the array, or -1 if the array did not contain the targetValue */ var doSearch = function(array, targetValue) { var min = 0; var max = array.length - 1; var guess; while(min < max) { guess = (max + min) / 2; if (array
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