bet

App “does not contain the correct beta entitlement”

匿名 (未验证) 提交于 2019-12-03 02:11:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I submitted an application for review and I notice that the build that I submitted has an issue associated with it saying that Build 168 does not contain the correct beta entitlement. I wasn't able to find information on this error anywhere. What does it mean and will it inhibit the review process? My app was submitted today with Xcode 5.1.1 for iOS 7 (not the Xcode GM). Perhaps this relates to Testflight? 回答1: Please regenerate your provisioning profile. It will Fix this problem it's because the missing entitlement is now there

Java - Best way to grab ALL Strings between two Strings? (regex?)

匿名 (未验证) 提交于 2019-12-03 02:06:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This question has been bugging me for a long time now but essentially I'm looking for the most efficient way to grab all Strings between two Strings. The way I have been doing it for many months now is through using a bunch of temporary indices, strings, substrings, and it's really messy. (Why does Java not have a native method such as String substring(String start, String end) ? Say I have a String: abcabc [pattern1]foo[pattern2] abcdefg [pattern1]bar[pattern2] morestuff The end goal would be to output foo and bar . (And later to be added

R ggplot2 heatmap fixed scale color between graphs

匿名 (未验证) 提交于 2019-12-03 01:39:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I need to draw 3 different plots setting the same scale range color. I have 3 matrices with different range of values. For example: range ( matrixA ) # 0.60 0.85 range ( matrixB ) # 0.65 0.95 range ( matrixA ) # 0.5 1.0 I would like to have the same color fill for the plots. For example, for all 0.8 value in the difference plots, if in the first plot 0.8 orange, I want all 0.8 value in different graphs to be the same orange. My problem in this moment is: In the first plot, the color of the max value is red, then the value 0.85 is

Efficiently count number of entries between two std::multimap iterators

匿名 (未验证) 提交于 2019-12-03 01:33:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I would like to count the number of entries between two iterators of an std::multimap in less than O(N) time. Are there any tricks or clever ways to do this? Since std::multimap has bidirectional iterators, my understanding is that something like std::distance could do this in O(N) time. Additional details: The multimap 's key is an N-tuple. I'm trying to find the number of entries in the multimap whose key's first element is 0. The options for the first element of they key are 0 and 1, and the multimap uses a strict weak ordering

Docker Compose - Share named volume between multiple containers

匿名 (未验证) 提交于 2019-12-03 01:27:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I'm using docker-compose and v3. I'm trying to mount a volume in docker: ./appdata:/appdata I'd like to have this as a volume and then reference that volume from multiple containers. The volume configuration reference only shows data-volume: as a named volume, with no value, so it doesn't look like the above. services : nginx : build : ./ nginx / ports : - 80 : 80 links : - php volumes : - app - volume php : build : ./ php / expose : - 9000 volumes : - app - volume volumes : app - volume : ./ appdata :/ appdata This gives me: ERROR

App “does not contain the correct beta entitlement”

匿名 (未验证) 提交于 2019-12-03 01:25:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I submitted an application for review and I notice that the build that I submitted has an issue associated with it saying that Build 168 does not contain the correct beta entitlement. I wasn't able to find information on this error anywhere. What does it mean and will it inhibit the review process? My app was submitted today with Xcode 5.1.1 for iOS 7 (not the Xcode GM). Perhaps this relates to Testflight? 回答1: Please regenerate your provisioning profile. It will Fix this problem it's because the missing entitlement is now there beta-reports

Getting the old value and new value between two revisions with Hibernate Envers

匿名 (未验证) 提交于 2019-12-03 01:10:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: This is a follow up question to Retrieve audited entities name, old value and new value of the given revision I have figured out how to get the two revision of an entity but don't see any easy to find the difference between the two. Is there anything in envers that will help doing a diff of an entity at different revisions? Or any good libraries? I would be really cool if I could get the property modified (_mod) field fields. 回答1: So what I came up with to make life easier was to create an annotation to mark the fields I was interested in

Pwnable-blackjack

喜夏-厌秋 提交于 2019-12-02 21:41:59
游戏源码 http://cboard.cprogramming.com/c-programming/114023-simple-blackjack-program.html 打开之后是一个游戏 你有500本金,赢到一百万才有flag 每次下注不能超过本金,运气好都要很久,更何况还会输,那么我们看看这个游戏的源码,但是 于是我窃了一下其他的博客的源码(读书人能叫偷吗) int betting() //Asks user amount to bet { printf("\n\nEnter Bet: $"); scanf("%d", &bet); if (bet > cash) //If player tries to bet more money than player has { printf("\nYou cannot bet more money than you have."); printf("\nEnter Bet: "); scanf("%d", &bet); return bet; } else return bet; } // End Function 可以看到这里,第一次判断如果下注超过本金,则告诉你没有那么多钱,并且让你在输入一次,重点是第二次输入的本金没有进行二次判断是否大于本金,于是我们就可以利用这里逻辑漏洞:第一次故意故意输入大于500,第二次输入一百万

Shell 编程 文本处理工具 sed

前提是你 提交于 2019-12-01 09:42:40
本篇主要写一些 shell 脚本文本处理工具 sed 的使用。 概述 sed(Stream EDitor) 是一个强大而简单的文本解析转换工具,可以读取文本,并根据指定的条件对文本内容进行编辑(删除、替换、添加、移动等),最后输出所有行或者仅输出处理的某些行。 sed 也可以在无交互的情况下实现相复杂的文本处理操作,被广泛应用于 Shell 脚本中,用以完成各种自动化处理任务。 sed 的工作流程主要包括读取、执行和显示三个过程: 读取: sed 从输入流(文件、管道、标准输入)中读取一行内容并存储到临时的缓冲区中(又称模式空间, pattern space ) 执行:默认情况下,所有的 sed 命令都在模式空间中顺序地执行,除非指定了行的地址,否则 sed 命令将会在所有的行上依次执行 显示:发送修改后的内容到输出流。再发送数据后,模式空间将会被清空 在所有的文件内容都被处理完成之前,上述过程将重复执行,直至所有内容被处理完。 默认情况下,所有的 sed 命令都是在模式空间内执行的,因此输入的文件并不会发生任何变化,除非是用重定向存储输出。 命令常见用法 命令有两种格式: sed [选项] '操作' 参数 sed [选项] -f scriptfile 参数 常见的命令选项 -e 或 --expression= :表示用指定命令或者脚本来处理输入的文本文件 -f 或 --file=

Shell 编程 正则表达式

蓝咒 提交于 2019-12-01 09:34:48
本篇主要写一些 shell 脚本正则表达式的使用基础。 概述 正则表达式分为基础正则表达式(Regular Expression)与扩展正则表达式(Extended Regular Expression)。 它不是一个工具程序,而是一个字符串处理的标准依据,是使用单个字符串搜索、匹配一系列符合某个语法规则的字符串。 它由普通字符(a~z)以及特殊字符(元字符)组成。 linux 文本处理工具 文本处理工具 基础正则表达式 扩展正则表达式 vi编辑器 支持 / grep 支持 / egrep 支持 支持 sed 支持 / awk 支持 支持 基础正则表达式 基础正则表达式常见元字符 ^ :匹配输入字符串的开始位置。在方括号表达式中使用,表示不包含该字符集合。要匹配 ^ 字符本身,使用 \^ $ :匹配输入字符串的结尾位置。如果设置了 RegExp 对象的 Multiline 属性,则 $ 也匹配 \n 或 \r 。要匹配 $ 字符本身,请使用 \$ . :匹配除 \r\n 之外的任何单个字符 \ :将下一个字符标记为特殊字符、原义字符、向后引用、八进制转义符。例如, n 匹配字符 n 。 \n 匹配换行符。序列 \\ 匹配 \ ,而 \( 则匹配 ( * :匹配前面的子表达式零次或多次。要匹配 * 字符,请使用 \* [] :字符集合。匹配所包含的任意一个字符。例如, [abc]