android-file

Is it possible to create and maintain a folder structure with files Using the Internal Storage

由 守給你的承諾、 提交于 2019-12-06 12:00:26
I have studied the link below, but it doesn't answer my question. http://developer.android.com/guide/topics/data/data-storage.html#filesInternal If the answer to the question in the title is yes. Could someone please supply a simple example creating a subfolder and adding a file to that folder? And perhaps show how to read the file back from the sub folder? Or maybe tell me why the example below fails miserably Works now after changing file.mkdirs(); to file.getParentFile().mkdirs(); Se explanation in the following Answer public static void Test(String path, String fileName, String fileStr,

How to share *.txt file in android

由 徘徊边缘 提交于 2019-12-06 04:25:56
问题 I tried many ways but i can't do this . I have a *.txt file . i want share it via Bluetooth , wifi , email and ... . When i used this code i cant share the file: File file = new File(Environment.getExternalStorageDirectory(), "Email-Ghap/Emails.txt"); Intent sharingIntent = new Intent(Intent.ACTION_SEND); sharingIntent.setType("*/txt"); sharingIntent.putExtra(Intent.EXTRA_STREAM, file); startActivity(Intent.createChooser(sharingIntent, "share file with")); Totally i want this : when user

What is the maximum file path allowed in Android

由 喜欢而已 提交于 2019-12-06 02:31:34
问题 The question here talks about file name length limit, I'm interested in the overall permitted path length (if it matters). There's this filesystems limits table here, though I'm not sure which applies to Android of which version. 回答1: I tested with 1024 characters long path and it works in every device I tested on. I didn't go further up, maybe it mess up the sd card. I think, max file name length should be less than 128 and max file path length should be less than 1024 for Android. Again

Reading a cache file previously written by the same app

由 笑着哭i 提交于 2019-12-06 02:29:56
问题 I'm writing to a file using the code below: File file = new File(getCacheDir(), "cachefile"); FileOutputStream fos = new FileOutputStream(file); StringBuilder cachetext = new StringBuilder(); Iterator bri = brands.iterator(); Iterator bli = brand_id.iterator(); while(bli.hasNext()) { cachetext.append(bli.next() + "|" + bri.next() + System.getProperty("line.separator")); } fos.write(cachetext.toString().getBytes()); fos.close(); This works fine - no errors and the file ends up containing what

new File(path) always actually creates a file on android?

由 喜欢而已 提交于 2019-12-05 19:21:17
I am trying to check if a file exits on android sd card...so i do: File f=new File(sdpath + "/" + DATABASE_NAME); // if(!f.exits()) { ...create new file.. } else { ...do something... } Every time this actually creates the directory or file on the sd card. I know it doesnt exist, and when the new File is executed it is created and it shouldnt ? I read all across google that new File doesnt create an actual file on the file system , but in my case it does... Any alternatives to checking if a File/directory exits without using new File.. Edit 1: Well I'd just like to add (after 4 years :)) that

How to show preview of file and open up file in its application in Android?

由 大憨熊 提交于 2019-12-05 11:45:05
I have a option to attach files within a application. I this I need to show users a preview or a icon for specific item type. Icons with extension .txt, .doc, .pdf, .jpeg, .mp4 need to have its own specific icons or if possible a good preview thumbnail icon. And when the user wants to view it he would be clicking on the icon or preview. I need to start a intent to view the file. I mean a pdf should open up in a pdf reader, or a txt or doc should open in text reader, a mp3 or mp4 should open up in a audio or video player.. and the important part I want them to com back to my application when

Android - Passing simple string over Wi-fi?

由 牧云@^-^@ 提交于 2019-12-05 04:11:35
问题 I have Wi-fi direct demo. In that we can transfer any image files to other devices. When another device get connected and it shows to send image from gallery. And at other side it shows sent image. But I want to send a simple string and at other side I want to toast that string. Here I am posting a code in which they have implemented file transfer. I am very confused in this code. I am not getting where to change to pass only string. Please help me. Thanks. DeviceDetailFragment.java /** * A

Android File Provider Illegal Argument Exception

由 元气小坏坏 提交于 2019-12-04 23:35:44
I am using file provider to save photo to a given destination. I get: java.lang.IllegalArgumentException: Missing android.support.FILE_PROVIDER_PATHS meta-data while trying to open activity to capture image from camera. My manifest.xml file: <provider android:name="android.support.v4.content.FileProvider" android:authorities="com.example" android:exported="false" android:grantUriPermissions="true"> <meta-data android:name="android.support.FILE_PROVIDER_PATHS" android:resource="@xml/paths" /> </provider> My paths.xml file: <paths xmlns:android="http://schemas.android.com/apk/res/android">

Android, how to choose save file location?

由 廉价感情. 提交于 2019-12-04 18:31:50
问题 is there any solution how to choose the saving files location? maybe with the original file browser, to choose the destination? thank you! 回答1: All you need is Android Directory Picker 回答2: Better to save files with your app namespace: String extStorage = Environment.getExternalStorageState(); path = extStorage+"/Android/data/com.mydomain.myapp/"; It will be deleted when app gets uninstalled. Here is actually everything about data storing. http://developer.android.com/guide/topics/data/data

Convert a file (<100Mo) in Base64 on Android

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-04 17:28:50
问题 I am trying to convert a file from the sdcard to Base64 but it seems the file is too big and i get an OutOfMemoryError. Here is my code : InputStream inputStream = null;//You can get an inputStream using any IO API inputStream = new FileInputStream(file.getAbsolutePath()); byte[] bytes; byte[] buffer = new byte[8192]; int bytesRead; ByteArrayOutputStream output = new ByteArrayOutputStream(); try { while ((bytesRead = inputStream.read(buffer)) != -1) { output.write(buffer, 0, bytesRead); } }
订阅 android-file