addition

I am trying to build up subtraction, addition, division, multiplication and other operations using only following ones: incr(x) - Once this function is called it will assign x + 1 to x assign(x, y) - This function will assign the value of y to x (x = y) zero(x) - This function will assign 0 to x (x = 0) loop X { } - operations written within brackets will be executed X times Using following rules it is straight forward to implement addition (add) like this: ADD (x, y) { loop X { y = incr (y) } return y } However, I'm struggling to implement subtraction . I think that all the other needed

I hear this statement quite often, that multiplication on modern hardware is so optimized that it actually is at the same speed as addition. Is that true? I never can get any authoritative confirmation. My own research only adds questions. The speed tests usually show data that confuses me. Here is an example: #include <stdio.h> #include <sys/time.h> unsigned int time1000() { timeval val; gettimeofday(&val, 0); val.tv_sec &= 0xffff; return val.tv_sec * 1000 + val.tv_usec / 1000; } int main() { unsigned int sum = 1, T = time1000(); for (int i = 1; i < 100000000; i++) { sum += i + (i+1); sum++;

can anybody tell me how to add up these variables: var preciopag = document.valores.T1.value; var libras = document.valores.T2.value; var serviciocom = 5.00 var contador1 = 0; var contador2 = 0; var tramite = 0; var enviopty = 0; var ITBMS = 0; var Total = preciopag + serviciocom + enviopty + tramite + ITBMS; Thanks in advance. The value of elements is always a string , so + will result in concatenation , not addition. Convert from string to number when retrieving the values: var preciopag = +document.valores.T1.value; var libras = +document.valores.T2.value; There I've used + , which will

What I'm trying to do is take two lists and add them together like each list is a whole number. (define (reverse lst) (if (null? lst) '() (append (reverse (cdr lst)) (list (car lst))))) (define (apa-add l1 l2) (define (apa-add-help l1 l2) (cond ((and (null? l1) (null? l2)) '()) ((null? l1) (list (+ (apa-add-help '() (cdr l2))))) ((null? l2) (list (+ (apa-add-help (cdr l1) '())))) ((>= (+ (car l1) (car l2)) 10) (append (apa-add-help (cdr l1) (cdr l2)) (list (quotient (+ (car l1) (car l2)) 10)) (list (modulo (+ (car l1) (car l2)) 10)))) ;this is a problem (else (append (apa-add-help (cdr l1)

I am trying to cycle through the entire alphabet using Swift. The only problem is that I would like to assign values to each letter. For Example: a = 1, b = 2, c = 3 and so on until I get to z which would = 26. How do I go through each letter in the text field that the user typed while using the values previously assigned to the letters in the alphabet? After this is done, how would I add up all the letters values to get a sum for the entire word. I am looking for the simplest possible way to accomplish this but works the way I would like it to. Any suggestions? Thanks in Advance. edit/update:

While looking through some c header files (specifically stdarg.h ), I noticed a very peculiar line: #if !defined(__STRICT_ANSI__) || __STDC_VERSION__ + 0 >= 199900L The strange part is the + 0 . Zero is the additive identity; it's one of the various math has of writing noop . What purpose does adding zero have in the above preprocessor statement? I know that there's all sorts of weird preprocessor magic out there, but this just seems ridiculous. That avoids a preprocessor syntax error if __STDC_VERSION__ is defined as an empty token (e.g. with #define __STDC_VERSION__ ). (Thanks to Jens

I was testing some of my code, in javascript I added .1+.2 and it gives me .30000000000000004 instead of .3 . I don't understand this. But when I added .1+.3 it gives me .4. I googled it and find its something about Double Precision addition. But I don't know what it is. Here's the obligatory link: What Every Computer Scientist Should Know About Floating-Point Arithmetic Basically, there are many base 10 numbers that cannot be exactly represented in the floating point format used by most computers, so you'll get issues like the ones you highlight. If you can't stay awake for What Every

Possible Duplicate: python - decimal place issues with floats Python float equality weirdness In the code below I have the variable percentage which is a float. I have it set up so that the if number reaches 10,000 , percentage is suppose to go up by .01 . # Tries to find a number that when squared and 5%'ed is still a square. import math print("Script has started:\n") percentage = .1 number = 1 while number != -1: number = number + 1 num_powered = number ** 2 num_5per = num_powered * percentage num_5per_sqrt = math.sqrt(num_5per) num_list = list(str(num_5per_sqrt)) dot_location = num_list