addition

Say I have four 32-bit numbers, defined so that their bits don't overlap, i.e. unsigned long int num0 = 0xFF000000; unsigned long int num1 = 0x00FF0000; unsigned long int num2 = 0x0000FF00; unsigned long int num3 = 0x000000FF; Where in each number one could have anything in the place of the FF s. Am I right in saying that addition and bitwise or would always produce the same output for such sort of numbers? Thanks! as long as for two numbers num1 and num2 applies num1 & num2 == 0 , then follows: num1 + num2 == num1 | num2 the reason for this is, that addition is basically a bitwise XOR, plus

I was optimising some Python code, and tried the following experiment: import time start = time.clock() x = 0 for i in range(10000000): x += 1 end = time.clock() print '+=',end-start start = time.clock() x = 0 for i in range(10000000): x -= -1 end = time.clock() print '-=',end-start The second loop is reliably faster, anywhere from a whisker to 10%, depending on the system I run it on. I've tried varying the order of the loops, number of executions etc, and it still seems to work. Stranger, for i in range(10000000, 0, -1): (ie running the loop backwards) is faster than for i in range(10000000)

I would like to do an update by doing a simple addition on Sequelize. table: id || data 1 || 10 sample: db.table.update({ data : 1 }, { where: { id: 1 }}); after this query id || data 1 || 11 I know it's a simple question, but I could not find the solution. Which operator can I add and subtract? Thank you Here it is : db.table.update({ field: Sequelize.literal('data + 1') }, { where: { id: 1 }})) OR User.findById(1).then(user => { // -----> First Way return user.increment('my-integer-field', {by: 2}); // -----> Second Way return user.increment([ 'my-integer-field', 'my-very-other-field' ], {by

Yeah thanks that works. @PeterCordes. Also __int128 works. But one more thing as you said using the intrinsics of multiprecision arithmetic that is _addcarry_u64 in C, using the header file immintrin.h I have the following code #include <stdio.h> #include <stdlib.h> #include <stdint.h> #include <immintrin.h> unsigned char _addcarry_u64(unsigned char c_in, uint64_t src1, uint64_t src2,uint64_t *sum); int main() { unsigned char carry; uint64_t sum; long long int c1=0,c2=0; uint64_t a=0x0234BDFA12CD4379,b=0xA8DB4567ACE92B38; carry = _addcarry_u64(0,a,b,&sum); printf("sum is %lx and carry value is

Through my javascript library, I end up with a string that represents a number. Now I want to preform an addition on that number without it doing a string concatenation instead. The solution is easy ( How do I add an integer value with javascript (jquery) to a value that's returning a string? , How to make an addition instead of a concatenation ) if your number is always in integer. However my string could be a float or an integer, and at the time of the addition, and I don't know which it will be. Is there a way to make sure the addition happens regardless of whether it's a float or integer?