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Algorithm: 学习算法
题目:valid-sudoku(有效的数独)
描述:判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。
- 数字 1-9 在每一行只能出现一次。
- 数字 1-9 在每一列只能出现一次。
- 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。
上图是一个部分填充的有效的数独。
数独部分空格内已填入了数字,空白格用 '.'
表示。
示例 1:
输入:
[
["5","3",".",".","7",".",".",".","."],
["6",".",".","1","9","5",".",".","."],
[".","9","8",".",".",".",".","6","."],
["8",".",".",".","6",".",".",".","3"],
["4",".",".","8",".","3",".",".","1"],
["7",".",".",".","2",".",".",".","6"],
[".","6",".",".",".",".","2","8","."],
[".",".",".","4","1","9",".",".","5"],
[".",".",".",".","8",".",".","7","9"]
]
输出: true
说明:
- 一个有效的数独(部分已被填充)不一定是可解的。
- 只需要根据以上规则,验证已经填入的数字是否有效即可。
- 给定数独序列只包含数字 1-9 和字符 '.' 。
- 给定数独永远是 9x9 形式的
解题过程:
利用 set 不重复保存的特性,将数独元素存入set中,如果不能保存,就判断为无效。
精髓是给数字按不同维度标记。因为要数字不重复, 那么可以给每个数字在 行、列、九宫格 里 分别给到不同的标识,比如
- 第四行的7,记为"(7) in line 4"
- 第四列的7,记为"(7) in column 4"
- 在右上角的九宫格的7,记为"(7) in (0,3)"
解法:
1 import java.util.HashSet; 2 import java.util.Set; 3 4 /** 5 * description : https://leetcode.com/problems/valid-sudoku/ 6 * 题目描述 : https://leetcode-cn.com/problems/valid-sudoku/ 7 */ 8 public class ValidSudoku { 9 10 public boolean isValidSudoku(char[][] board) { 11 Set seen = new HashSet(); 12 for (int i = 0; i < 9; ++i) { 13 for (int j = 0; j < 9; ++j) { 14 char number = board[i][j]; 15 if (number != '.') 16 if (!seen.add(number + " in row " + i) || 17 !seen.add(number + " in column " + j) || 18 !seen.add(number + " in block " + i / 3 + "-" + j / 3)) 19 return false; 20 } 21 } 22 return true; 23 } 24 }
Review: 学习英文
题目:
Tips: 知识点
如何在linux服务器 后台运行一个程序?
参考这篇文章 :Linux命令之nohup 和 重定向
Share: 价值观