This question already has an answer here:
- Easy way to concatenate two byte arrays 12 answers
I have two byte[]
arrays which are of unknown length and I simply want to append one to the end of the other, i.e.:
byte[] ciphertext = blah;
byte[] mac = blah;
byte[] out = ciphertext + mac;
I have tried using arraycopy()
but can't seem to get it to work.
Using System.arraycopy()
, something like the following should work:
// create a destination array that is the size of the two arrays
byte[] destination = new byte[ciphertext.length + mac.length];
// copy ciphertext into start of destination (from pos 0, copy ciphertext.length bytes)
System.arraycopy(ciphertext, 0, destination, 0, ciphertext.length);
// copy mac into end of destination (from pos ciphertext.length, copy mac.length bytes)
System.arraycopy(mac, 0, destination, ciphertext.length, mac.length);
Perhaps the easiest way:
ByteArrayOutputStream output = new ByteArrayOutputStream();
output.write(ciphertext);
output.write(mac);
byte[] out = output.toByteArray();
You need to declare out
as a byte array with a length equal to the lengths of ciphertext
and mac
added together, and then copy ciphertext
over the beginning of out
and mac
over the end, using arraycopy.
byte[] concatenateByteArrays(byte[] a, byte[] b) {
byte[] result = new byte[a.length + b.length];
System.arraycopy(a, 0, result, 0, a.length);
System.arraycopy(b, 0, result, a.length, b.length);
return result;
}
The other provided solutions are great when you want to add only 2 byte arrays, but if you want to keep appending several byte[] chunks to make a single:
byte[] readBytes ; // Your byte array .... //for eg. readBytes = "TestBytes".getBytes();
ByteArrayBuffer mReadBuffer = new ByteArrayBuffer(0 ) ; // Instead of 0, if you know the count of expected number of bytes, nice to input here
mReadBuffer.append(readBytes, 0, readBytes.length); // this copies all bytes from readBytes byte array into mReadBuffer
// Any new entry of readBytes, you can just append here by repeating the same call.
// Finally, if you want the result into byte[] form:
byte[] result = mReadBuffer.buffer();
First you need to allocate an array of the combined length, then use arraycopy to fill it from both sources.
byte[] ciphertext = blah;
byte[] mac = blah;
byte[] out = new byte[ciphertext.length + mac.length];
System.arraycopy(ciphertext, 0, out, 0, ciphertext.length);
System.arraycopy(mac, 0, out, ciphertext.length, mac.length);
I wrote the following procedure for concatenation of several array:
static public byte[] concat(byte[]... bufs) {
if (bufs.length == 0)
return null;
if (bufs.length == 1)
return bufs[0];
for (int i = 0; i < bufs.length - 1; i++) {
byte[] res = Arrays.copyOf(bufs[i], bufs[i].length+bufs[i + 1].length);
System.arraycopy(bufs[i + 1], 0, res, bufs[i].length, bufs[i + 1].length);
bufs[i + 1] = res;
}
return bufs[bufs.length - 1];
}
It uses Arrays.copyOf
来源:https://stackoverflow.com/questions/5368704/appending-a-byte-to-the-end-of-another-byte