问题
Given a dataframe column which is a series of integers (age), I want to convert ranges of integers into ordinal variables.
My current code doesn\'t work, how do I do this?
df <- read.table(\"http://dl.dropbox.com/u/822467/df.csv\", header = TRUE, sep = \",\")
df[(df >= 0) & (df <= 14)] <- \"Age1\"
df[(df >= 15) & (df <= 44)] <- \"Age2\"
df[(df >= 45) & (df <= 64)] <- \"Age3\"
df[(df > 64)] <- \"Age4\"
table(df)
回答1:
Use cut
to do this in one step:
dfc <- cut(df$x, breaks=c(0, 15, 45, 56, Inf))
str(dfc)
Factor w/ 4 levels "(0,15]","(15,45]",..: 3 4 3 2 2 4 2 2 4 4 ...
Once you are satisfied that the breaks
are correctly specified, you can then also use the labels
argument to relabel the levels:
dfc <- cut(df$x, breaks=c(0, 15, 45, 56, Inf), labels=paste("Age", 1:4, sep=""))
str(dfc)
Factor w/ 4 levels "Age1","Age2",..: 3 4 3 2 2 4 2 2 4 4 ...
来源:https://stackoverflow.com/questions/10222525/replacing-numbers-within-a-range-with-a-factor