Print integer with thousands and millions separator

问题

Got a question about printing Integers with thousands/millions separator.

I got a Textfile where i got Country, City,Total Population.

I have to read in the File, and sort by country. If country is eual, i have to sort descending by population.

Textfile is like:

Australia........Sydney.........10.123.456

Brazil...........Sao Paulo.......7.123.345

I read all 3 into a seperated string. Then i erase all "." in the population string. Then i use atoi() to cast the population string to an integer.

Now i can sort by population if country is equal. This sort works correctly.

So far so good. But i need to get thousand/millions seperator into the printing of the population.

If i use string,with the "." for population, sorting dont work correctly. Its sorted like:

x........x......1.123456

x........x......10.123.456

x........x......2.123.232

It have to look like:

Australia........Sydney.........10.123.456

Australia........Brisbane.......8.123.456

Is there a way to manipulate the printing by adding separator the the int again?

Many Thanks in advance

回答1:

imbue() the output stream with a locale that has the desired separator. For example:

#include <iostream>
#include <locale>

int main()
{
    // imbue the output stream with a locale.
    int i = 45749785;
    std::cout << i << "\n";

    std::cout.imbue(std::locale(""));
    std::cout << i << "\n";
}

Output on my machine (and online demo):

45749785
45,749,785

As commented, and answered, by James Kanze imbue the input stream also to read the separated int values without manually modifying the input.

See Stroustrop's Appendix D: Locales for a detailed overview of locales.

回答2:

Use a locale which supports the desired separators to read the file (that way you can read the values as integers), and the same locale to write the data.

Note that you may not have such a locale available, or if you do, you may not know its name (and using a named locale might change other things, that you don't want changed); on my machine, imbueing with "" behaves differently according to the compiler (or maybe the shell I'm invoking it from)—you should never use the locale "" if you have strict formatting requirements. (The use of locale "" is for the case when you want the format to depend on the users environment specifications.)

In this case, it's probably better to provide the local explicitly:

class MyNumPunct : public std::numpunct<char>
{
protected:
    virtual char do_thousands_sep() const { return ','; }
    virtual std::string do_grouping() const { return "\03"; }
};

int
main()
{
    std::cout.imbue( std::locale( std::locale::classic(), new MyNumPunct ) );
    std::cout << 123456789 << std::endl;
    return 0;
}

Of course, you'll want to use this locale for the input as well. (This code will give you the "C" locale, with only the grouping changed.)

来源：https://stackoverflow.com/questions/17530408/print-integer-with-thousands-and-millions-separator

标签

c++

fstream

separator