问题
I wanted to this:
for i := 0; i < len(str); i++ {
dosomethingwithrune(str[i]) // takes a rune
}
But it turns out that str[i]
has type byte
(uint8
) rather than rune
.
How can I iterate over the string by runes rather than bytes?
回答1:
See this example from Effective Go :
for pos, char := range "日本語" {
fmt.Printf("character %c starts at byte position %d\n", char, pos)
}
This prints :
character 日 starts at byte position 0
character 本 starts at byte position 3
character 語 starts at byte position 6
For strings, the range does more work for you, breaking out individual Unicode code points by parsing the UTF-8.
回答2:
For example:
package main
import "fmt"
func main() {
for i, rune := range "Hello, 世界" {
fmt.Printf("%d: %c\n", i, rune)
}
}
Playground
Output:
0: H
1: e
2: l
3: l
4: o
5: ,
6:
7: 世
10: 界
回答3:
To mirror an example given at golang.org, Go allows you to easily convert a string to a slice of runes and then iterate over that, just like you wanted to originally:
runes := []rune("Hello, 世界")
for i := 0; i < len(runes) ; i++ {
fmt.Printf("Rune %v is '%c'\n", i, runes[i])
}
Of course, we could also use a range operator like in the other examples here, but this more closely follows your original syntax. In any case, this will output:
Rune 0 is 'H'
Rune 1 is 'e'
Rune 2 is 'l'
Rune 3 is 'l'
Rune 4 is 'o'
Rune 5 is ','
Rune 6 is ' '
Rune 7 is '世'
Rune 8 is '界'
Note that since the rune
type is an alias for int32
, we must use %c
instead of the usual %v
in the Printf
statement, or we will see the integer representation of the Unicode code point (see A Tour of Go).
来源:https://stackoverflow.com/questions/18130859/how-can-i-iterate-over-a-string-by-runes-in-go