rune

问题 I wanted to this: for i := 0; i < len(str); i++ { dosomethingwithrune(str[i]) // takes a rune } But it turns out that str[i] has type byte ( uint8 ) rather than rune . How can I iterate over the string by runes rather than bytes? 回答1: See this example from Effective Go : for pos, char := range "日本語" { fmt.Printf("character %c starts at byte position %d\n", char, pos) } This prints : character 日 starts at byte position 0 character 本 starts at byte position 3 character 語 starts at byte position

问题 I wanted to this: for i := 0; i < len(str); i++ { dosomethingwithrune(str[i]) // takes a rune } But it turns out that str[i] has type byte ( uint8 ) rather than rune . How can I iterate over the string by runes rather than bytes? 回答1: See this example from Effective Go : for pos, char := range "日本語" { fmt.Printf("character %c starts at byte position %d\n", char, pos) } This prints : character 日 starts at byte position 0 character 本 starts at byte position 3 character 語 starts at byte position

问题 I've discovered the following peculiarity: b := "a"[0] r := 'a' fmt.Println(b == r) // Does not compile, cannot compare byte and rune fmt.Println("a"[0] == 'a') // Compiles and prints "true" How does this work? 回答1: This is an example of untyped constants. From the docs: Untyped boolean, numeric, and string constants may be used as operands wherever it is legal to use an operand of boolean, numeric, or string type, respectively. Except for shift operations, if the operands of a binary

问题 I've discovered the following peculiarity: b := "a"[0] r := 'a' fmt.Println(b == r) // Does not compile, cannot compare byte and rune fmt.Println("a"[0] == 'a') // Compiles and prints "true" How does this work? 回答1: This is an example of untyped constants. From the docs: Untyped boolean, numeric, and string constants may be used as operands wherever it is legal to use an operand of boolean, numeric, or string type, respectively. Except for shift operations, if the operands of a binary

问题 I've discovered the following peculiarity: b := "a"[0] r := 'a' fmt.Println(b == r) // Does not compile, cannot compare byte and rune fmt.Println("a"[0] == 'a') // Compiles and prints "true" How does this work? 回答1: This is an example of untyped constants. From the docs: Untyped boolean, numeric, and string constants may be used as operands wherever it is legal to use an operand of boolean, numeric, or string type, respectively. Except for shift operations, if the operands of a binary

问题 I've discovered the following peculiarity: b := "a"[0] r := 'a' fmt.Println(b == r) // Does not compile, cannot compare byte and rune fmt.Println("a"[0] == 'a') // Compiles and prints "true" How does this work? 回答1: This is an example of untyped constants. From the docs: Untyped boolean, numeric, and string constants may be used as operands wherever it is legal to use an operand of boolean, numeric, or string type, respectively. Except for shift operations, if the operands of a binary

问题 I have the following code, it is supposed to cast a rune into a string and print it. However, I am getting undefined characters when it is printed. I am unable to figure out where the bug is: package main import ( "fmt" "strconv" "strings" "text/scanner" ) func main() { var b scanner.Scanner const a = `a` b.Init(strings.NewReader(a)) c := b.Scan() fmt.Println(strconv.QuoteRune(c)) } 回答1: That's because you used Scanner.Scan() to read a rune but it does something else. Scanner.Scan() can be

问题 I have the following code, it is supposed to cast a rune into a string and print it. However, I am getting undefined characters when it is printed. I am unable to figure out where the bug is: package main import ( "fmt" "strconv" "strings" "text/scanner" ) func main() { var b scanner.Scanner const a = `a` b.Init(strings.NewReader(a)) c := b.Scan() fmt.Println(strconv.QuoteRune(c)) } 回答1: That's because you used Scanner.Scan() to read a rune but it does something else. Scanner.Scan() can be

问题 What is a rune in Go? I've been googling but Golang only says in one line: rune is an alias for int32 . But how come integers are used all around like swapping cases? The following is a function swapcase. What is all the <= and - ? And why doesn't switch have any arguments? && should mean and but what is r <= 'z' ? func SwapRune(r rune) rune { switch { case 'a' <= r && r <= 'z': return r - 'a' + 'A' case 'A' <= r && r <= 'Z': return r - 'A' + 'a' default: return r } } Most of them are from

问题 I have a string stored as a : a := `M\u00fcnchen` fmt.Println(a) // prints "M\u00fcnchen" b := "M\u00fcnchen" fmt.Println(b) // prints "München" Is there a way I can convert a into b ? 回答1: You can use strconv.Unquote for this: u := `M\u00fcnchen` s, err := strconv.Unquote(`"` + u + `"`) if err != nil { // .. } fmt.Printf("%v\n", s) Outputs: München 来源： https://stackoverflow.com/questions/35519106/how-to-decode-a-string-containing-backslash-encoded-unicode-characters