Expand tuple into arguments while casting them? [duplicate]

问题

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Call int() function on every list element? (7 answers)

Closed 4 years ago.

I have this:

blah = random.randint(int(minmax[0]), int(minmax[1]))

I know this is possible:

minimum, maximum = int(minmax[0]), int(minmax[1])
blah = random.randint(minimum, maximum)

Can I do this second one in a single line using tuple-argument expansion? For example, if minmax was a tuple of integers to begin with, I could do:

blah = random.randint(*minmax)

But I don't have a tuple of ints, I have a tuple of strs. Obviously it's not a big deal one way or the other. I'm just curious.

回答1:

Yeah, that's doable:

blah = random.randint(*map(int, minmax))

Use map(int, ...) to perform the type conversion.

回答2:

You may use a list comprehension expression to type-cast the elements to int and then unpack the list as:

random.randint(*[int(i) for i in minmax])
#              ^    ^ type-cast minmax elements to `int`
#              ^ unpack the `list`   

来源：https://stackoverflow.com/questions/42011757/expand-tuple-into-arguments-while-casting-them