tuples

How to define a JSON array with concrete item definition for every index (i.e. a tuple) in OpenAPI?

纵饮孤独 提交于 2021-02-19 07:45:08
问题 I need to define in OpenAPI a JSON response with an array. The array always contains 2 items and the first one is always a number and second one is always a string. [1, "a"] //valid ["a", 1] //invalid [1] //invalid [1, "a", 2] //invalid I've found out that JSON schema does support that by passing a list of items in items instead of single object (source), but OpenAPI explicitly forbids that and accepts only a single object (source). How can that be expressed in OpenAPI? 回答1: OpenAPI 3.1

C# Tuple versus List Considerations

流过昼夜 提交于 2021-02-18 12:36:06
问题 The different attributes of Tuples and Lists; Tuples are heterogeneous and Lists are homogeneous, Tuples are immutable while Lists are mutable, often dictate the use of one type over the other. In other scenarios, however, either data type could be equally appropriate. As such , what are the memory and/or performance implications of Tuples versus Lists that might also guide our decision? Thanks, 回答1: Well, in addition to what you've mentioned there's the rather significant difference that a

Why does it work when I append a new element to a TUPLE?

|▌冷眼眸甩不掉的悲伤 提交于 2021-02-16 20:08:14
问题 Since Tuples are non-mutable data types in Python and Tuple comprehensions aren't a thing then why do List comprehensions with circle brackets instead of square brackets work fine and produce regular Tuples? I thought circular brackets were used to define Tuples not Lists (I know I'm not wrong there). From my understanding I'm appending values to a Tuple that has already been defined and I'm able to update a Tuple and that's not supposed to happen (in Python) as Tuples are non-mutable. I'm

Why does it work when I append a new element to a TUPLE?

本秂侑毒 提交于 2021-02-16 20:08:06
问题 Since Tuples are non-mutable data types in Python and Tuple comprehensions aren't a thing then why do List comprehensions with circle brackets instead of square brackets work fine and produce regular Tuples? I thought circular brackets were used to define Tuples not Lists (I know I'm not wrong there). From my understanding I'm appending values to a Tuple that has already been defined and I'm able to update a Tuple and that's not supposed to happen (in Python) as Tuples are non-mutable. I'm

Convert tuple of tuples to a dictionary with key value pair

眉间皱痕 提交于 2021-02-16 08:39:11
问题 I have the following tuple of tuples: tuples=((32, 'Network architectures', 5), (33, 'Network protocols', 5)) How could I turn it into a list of dictionary like this dict=[ {"id": 32, "name": "Network architectures", "parent_id": 5}, {"id": 33, "name": "Network protocols", "parent_id": 5}] 回答1: Using a list comprehension as follows. First create a list of keys which will repeat for all the tuples. Then just use zip to create individual dictionaries. tuples=((32, 'Network architectures', 5),

Convert tuple of tuples to a dictionary with key value pair

本小妞迷上赌 提交于 2021-02-16 08:37:55
问题 I have the following tuple of tuples: tuples=((32, 'Network architectures', 5), (33, 'Network protocols', 5)) How could I turn it into a list of dictionary like this dict=[ {"id": 32, "name": "Network architectures", "parent_id": 5}, {"id": 33, "name": "Network protocols", "parent_id": 5}] 回答1: Using a list comprehension as follows. First create a list of keys which will repeat for all the tuples. Then just use zip to create individual dictionaries. tuples=((32, 'Network architectures', 5),

python: cannot concatenate 'str' and 'tuple' objects (it should works!)

↘锁芯ラ 提交于 2021-02-16 04:47:51
问题 I have a code: print "bug " + data[str.find(data,'%')+2:-1] temp = data[str.find(data,'%')+2:-1] time.sleep(1) print "bug tuple " + tuple(temp.split(', ')) And after this my application displays: bug 1, 2, 3 Traceback (most recent call last): File "C:\Python26\Lib\site-packages\pythonwin\pywin\framework\scriptutils.py", line 312, in RunScript exec codeObject in main . dict File "C:\Documents and Settings\k.pawlowski\Desktop\atsserver.py", line 165, in print "bug tuple " + tuple(temp.split(',

python: cannot concatenate 'str' and 'tuple' objects (it should works!)

烂漫一生 提交于 2021-02-16 04:47:11
问题 I have a code: print "bug " + data[str.find(data,'%')+2:-1] temp = data[str.find(data,'%')+2:-1] time.sleep(1) print "bug tuple " + tuple(temp.split(', ')) And after this my application displays: bug 1, 2, 3 Traceback (most recent call last): File "C:\Python26\Lib\site-packages\pythonwin\pywin\framework\scriptutils.py", line 312, in RunScript exec codeObject in main . dict File "C:\Documents and Settings\k.pawlowski\Desktop\atsserver.py", line 165, in print "bug tuple " + tuple(temp.split(',

python: cannot concatenate 'str' and 'tuple' objects (it should works!)

别说谁变了你拦得住时间么 提交于 2021-02-16 04:43:47
问题 I have a code: print "bug " + data[str.find(data,'%')+2:-1] temp = data[str.find(data,'%')+2:-1] time.sleep(1) print "bug tuple " + tuple(temp.split(', ')) And after this my application displays: bug 1, 2, 3 Traceback (most recent call last): File "C:\Python26\Lib\site-packages\pythonwin\pywin\framework\scriptutils.py", line 312, in RunScript exec codeObject in main . dict File "C:\Documents and Settings\k.pawlowski\Desktop\atsserver.py", line 165, in print "bug tuple " + tuple(temp.split(',

'Tuple' object is not callable - Python

笑着哭i 提交于 2021-02-11 13:53:18
问题 I'm using pygame and I'm using a function that set the selected position of a text in PyGame : def textPos(YPos , TextSize): TextPosition.center(60,YPos) print("Size : " + TextSize) but when I run the program, I get an error: TextPosition.center(60,YPos) : TypeError : 'Tuple' object is not callable There's a way to solve this problem? 回答1: 'Tuple' object is not callable error means you are treating a data structure as a function and trying to run a method on it. TextPosition.center is a tuple