Read file with whitespace in name using Java?

问题

The original name of file is 1_00100 0042.jpg. I have a problem:

java.net.URISyntaxException: Illegal character in path at index 49: file:///opt/storage/user-data/attachments/1_00100\ 0042.jpg

Can you give me some solutions how to get this file using this bad path? I know that C# have Path class. Is there something similar in Java?

I tried to do next but not successfully:

private String replaceWhitespace(String str) {
    if (str.contains(" ")) {
        str = str.replace(" ", "%20");
    }
    return str;
}

回答1:

Use File, it works with whitespaces:

String path = "file:///opt/storage/user-data/attachments/1_00100\\ 0042.jpg";
File f = new File(path);

If you want to replace spaces with %20 then use regex:

path.replaceAll("\\u0020", "%20");

回答2:

I am not sure where did you get this path but I assume that \ before space was added to escape it so you need to change your method to also remove this \ before space.
Also since this method doesn't affect state of instance of your class you can make it static.

private static String replaceWhitespace(String str) {
    if (str.contains("\\ ")) {
        str = str.replace("\\ ", "%20");
    }
    return str;
}

Demo:

String file = "file:///opt/storage/user-data/attachments/1_00100\\ 0042.jpg";
file = replaceWhitespace(file);

URI u = new URI(file);
System.out.println(u.getRawPath());
System.out.println(u.getPath());

output:

/opt/storage/user-data/attachments/1_00100%200042.jpg
/opt/storage/user-data/attachments/1_00100 0042.jpg

来源：https://stackoverflow.com/questions/23828105/read-file-with-whitespace-in-name-using-java

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java

path