path

问题 I am trying to create a list with all possible paths in a tree. I have following structure given (subset from DB): text = """ 1,Product1,INVOICE_FEE, 3,Product3,INVOICE_FEE, 7,Product7,DEFAULT, 2,Product2,DEFAULT,7 4,Product4,DEFAULT,7 5,Product5,DEFAULT,2 """ where the columns are: ID, product-name, invoice-type, reference-to-parent-ID. I would like to create list with all possible paths, like in the example: [[Product1],[Product3],[Product7,Product2,Product5],[Product7,Product4]] I do

问题 I am trying to create a list with all possible paths in a tree. I have following structure given (subset from DB): text = """ 1,Product1,INVOICE_FEE, 3,Product3,INVOICE_FEE, 7,Product7,DEFAULT, 2,Product2,DEFAULT,7 4,Product4,DEFAULT,7 5,Product5,DEFAULT,2 """ where the columns are: ID, product-name, invoice-type, reference-to-parent-ID. I would like to create list with all possible paths, like in the example: [[Product1],[Product3],[Product7,Product2,Product5],[Product7,Product4]] I do

问题 I would like to zip folder in my project from CMake . For that I use following code snippet: ADD_CUSTOM_COMMAND ( TARGET ${PROJECT_NAME} PRE_BUILD COMMAND ${CMAKE_COMMAND} ARGS -E tar cvf ${ZIP_OUT_DIR}/my_archive.zip --format=zip -- ${FOLDER_TO_ZIP}/another_folder/ ) The problem with this code is that the files after unzipping contain path component ( ../../my_file.txt in my case). I tried to use tar cvf -C ${FOLDER_TO_ZIP}/another_folder but unfortunatelly CMake doesn't accept this option.

问题 This question already has answers here : How to find which elements are in the bag, using Knapsack Algorithm [and not only the bag's value]? (4 answers) Closed 6 days ago . I know how to solve knapsack 0-1 problem with dynamic programming approach, but I am having troubles figuring out which items to take without compromising the complexity of O(N * C) (N items, C capacity). Any ideas (I would prefer a bottom-up approach)? 回答1: Suppose, right now you're storing results in array bool[] a ,

问题 I am wondering how I can make my script save to the Desktop. Here's my code: from reportlab.pdfgen import canvas from reportlab.lib.pagesizes import letter from reportlab.platypus import Image import csv import os data_file = "hata.csv" def import_data(data_file): inv_data = csv.reader(open(data_file, "r")) for row in inv_data: var1 = row[0] # do more stuff pdf_file = os.path.abspath("~/Desktop/%s.pdf" % var1) generate_pdf(variable, pdf_file) def generate_pdf(variable, file_name): c = canvas

问题 I am wondering how I can make my script save to the Desktop. Here's my code: from reportlab.pdfgen import canvas from reportlab.lib.pagesizes import letter from reportlab.platypus import Image import csv import os data_file = "hata.csv" def import_data(data_file): inv_data = csv.reader(open(data_file, "r")) for row in inv_data: var1 = row[0] # do more stuff pdf_file = os.path.abspath("~/Desktop/%s.pdf" % var1) generate_pdf(variable, pdf_file) def generate_pdf(variable, file_name): c = canvas

问题 I am trying to glob all files&directories with gulp.src() expcept all directories starting with the character _ (i.e. _Stuff/ ). How can I achieve that? 回答1: Say you have a folder project/src that contains the following files: file.txt folder folder/file.txt folder/_subfolder folder/_subfolder/file.txt folder/subfolder folder/subfolder/file.txt _folder _folder/file.txt _folder/_subfolder _folder/_subfolder/file.txt _folder/subfolder _folder/subfolder/file.txt Then this task in project

问题 I am trying to glob all files&directories with gulp.src() expcept all directories starting with the character _ (i.e. _Stuff/ ). How can I achieve that? 回答1: Say you have a folder project/src that contains the following files: file.txt folder folder/file.txt folder/_subfolder folder/_subfolder/file.txt folder/subfolder folder/subfolder/file.txt _folder _folder/file.txt _folder/_subfolder _folder/_subfolder/file.txt _folder/subfolder _folder/subfolder/file.txt Then this task in project

问题 I've just started learning r and confused by the following question given in the course: Create a directory in the current working directory called “testdir2” and a subdirectory for it called “testdir3”, all in one command by using dir.create() and file.path(). I couldn't get it to accept my answer and then found another site online giving the answers. This is the answer the other site gave: dir.create(file.path('testdir2', 'testdir3'), recursive = TRUE) After copy/pasting this answer it

问题 This is probably a rudimentary question but I am still kinda new to programming and I've wondered for awhile. I've done multiple projects in Python, C#, and Java, and when I try to use new libraries (especially for Python) people always say to make sure its in the right PATH and such. I just followed an online tutorial on how to install Java on a new computer and it rekindled my question of what a path really is. Is the Path just were the programming language looks for a library in the file