Array Printing Java | 易学教程

问题

Basically I want my code to enable the user to enter x amount of integers (they chose x), then they will then store each of their inputted integer values in my array.

For some reason when I print my array out after all values have been entered:

I get this:

Code:

    Scanner input = new Scanner(System.in);
    System.out.print("How many integers will you enter:");
    int amount = input.nextInt();

    int myArray[] = new int[amount];

    for (int counter = 0; counter < amount; counter ++){
        myArray[counter] = input.nextInt();
    }
    System.out.println(myArray);

Console:

        How many integers will you enter:2
        4
        2
       [I@55f96302

回答1:

Ok, you can take away the for loop and do it this way

System.out.println(Arrays.toString(myArray));

I would strongly recommend to do it with the for loop. It prints one element at the time every time the loop runs, and with your for loop it runs through every element. You need to change the println to this (inside you for loop)

System.out.println(myArray[counter]);

or if you want to have the array on the same line

System.out.print(myArray[counter]+ " ");

Later on when programming you are going to see how useful this is compared to Arrays.toString() method.

回答2:

The string you get is the object notation of array which is expected [I@55f96302 where

[I is the class name
- [ one dimentional array
- I integer array
@ joins the string
55f96302 some hash code

To print array do

System.out.println(Arrays.toString(myArray));

or you can simply loop through each element of array

回答3:

You can also use java.util.ArrayList

ArrayList<Integer> myArray = new ArrayList<Integer>(amount);

for (int counter = 0; counter < amount; counter ++){
 myArray.add(counter,input.nextInt());
}
System.out.println(myArray);

prints array like this -> [1, 2, 3, 4]

来源：https://stackoverflow.com/questions/29520813/array-printing-java

标签

java

arrays

printing