Creating a linearly spaced array of a particular size

问题

I am new to MATLAB and currently working on my homework assignment. I am trying to declare the x variable as the following:

Create a linearly spaced array x of size (1 × 200) comprising values ranging from –pi to pi.

I've tried this code:

x=[-pi:200:pi];

but I'm not sure if it's the correct way to do this or not.

回答1:

You can use linspace as follow:

x = linspace(-pi, pi, 200);

check this out for an example: https://www.mathworks.com/help/matlab/ref/linspace.html

回答2:

The other answer shows how to use linspace, this is the correct method.

But you can also use the colon operator and some simple arithmetic to do this:

1. x = -pi : 2*pi/199 : pi -- This means: go from -π to π in steps of such a size that we get exactly 200 values.

2. x = (0:199) * (2*pi/199) - pi -- This means: create an array with 200 integer values, then scale them to the right range.

Note that you shouldn't use square brackets [] here. They are for concatenating arrays. The colon operator creates a single array, there is nothing to concatenate it with.

来源：https://stackoverflow.com/questions/54284753/creating-a-linearly-spaced-array-of-a-particular-size