问题
i have a general item string:
item='shoes'
then i use:
assign(paste0(item,'_list'),lapply(etc))
assign(paste0(item,'_df'),sapply(etc))
then i want to change the colnames of the data-frame with the names inside a character vector:
v=c('a','b','c')
i try to do:
colnames(get(paste0(item,'_df'))=v
bu i have the:
could not find function "get<-"
error
回答1:
I would create the names in the object being assign()
-ed. Not sure about chances of success with the second assignment, since I generally expect sapply
to return a matrix rather than a dataframe, which seems to be your expectation:
assign(paste0(item,'_list'), setNames(lapply(etc), v))
assign(paste0(item,'_df'), setNames(sapply(etc), v))
The names
function will work with lists, dataframes and vectors, but I think it's not particularly well matched with matrices. It doesn't throw an error (as I expected it would) but rather creates a names
attribute on a matrix that looks very out of place. In particular it does not set either rownames or colnames for a matrix. If you wanted something that did assign column names to a matrix this might succeed:
setColNames <- function (object = nm, nm)
{ if ( class(object) %in% c("list", "data.frame", "numeric", "character") ){
names(object) <- nm
return(object)
} else{
if ( class(object) %in% c("matrix") ){
colnames(object) <- nm
return(object)
} else { object }
}
}
来源:https://stackoverflow.com/questions/20481785/r-using-get-inside-colnames