Python tkinter cut down path but open as full directory

问题

Here is my full Python code:

from tkinter import *
import glob
import os
from PIL import Image, ImageTk, ImageGrab
import tkinter as tk
import pyautogui
import datetime

#date & time
now = datetime.datetime.now()

root = tk.Tk()
root.title("SIGN OFF")
root.minsize(840, 800)

# Add a grid
mainframe = tk.Frame(root)
mainframe.columnconfigure(0, weight=1)
mainframe.rowconfigure(0, weight=1)
mainframe.pack(pady=100, padx=100)

# Create a Tkinter variable
tkvar = tk.StringVar(root)


# Directory
directory = "C:/Users/eduards/Desktop/work/data/to-do"
choices = glob.glob(os.path.join(directory, "*.jpg"))
tkvar.set('...To Sign Off...') # set the default option

# Dropdown menu
popupMenu = tk.OptionMenu(mainframe, tkvar, *choices)
tk.Label(mainframe, text="Choose your sign off here:").grid(row=1, column=1)
popupMenu.grid(row=2, column=1)

label2 = tk.Label(mainframe, image=None)
label2.grid(row = 4, column = 1, rowspan = 10)

# On change dropdown callback.
def change_dropdown(*args):
    """ Updates label2 image. """
    imgpath = tkvar.get()
    img = Image.open(imgpath)
    img = img.resize((240,250))
    photo = ImageTk.PhotoImage(img)
    label2.image = photo
    label2.configure(image=photo)


tk.Button(mainframe, text="Open", command=change_dropdown).grid(row=3, column=1)


def var_states():
    text_file = open("logfile.txt", "a")
    text_file.write("TIME: %s, USER: %s, One %d, Two %d\n" % (now,os.getlogin(), var1.get(), var2.get()))
    text_file.close()
    print("One %d, Two %d" % (var1.get(), var2.get()))

var1 = IntVar()
Checkbutton(mainframe, text="Ingredients present in full (any allergens in bold with allergen warning if necessary)", variable=var1).grid(column = 2, row=1, sticky=W)
var2 = IntVar()
Checkbutton(mainframe, text="May Contain Statement.", variable=var2).grid(column = 2, row=2, sticky=W)
var3 = IntVar()
Checkbutton(mainframe, text="Cocoa Content (%).", variable=var3).grid(column = 2, row=3, sticky=W)
var4 = IntVar()
Checkbutton(mainframe, text="Vegetable fat in addition to Cocoa butter", variable=var4).grid(column = 2, row=4, sticky=W)
var5 = IntVar()
Checkbutton(mainframe, text="Instructions for Use.", variable=var5).grid(column = 2, row=5, sticky=W)
var6 = IntVar()
Checkbutton(mainframe, text="Additional warning statements (pitt/stone, hyperactivity etc)", variable=var6).grid(column = 2, row=6, sticky=W)
var7 = IntVar()
Checkbutton(mainframe, text="Nutritional Information Visible", variable=var7).grid(column = 2, row=7, sticky=W)
var8 = IntVar()
Checkbutton(mainframe, text="Storage Conditions", variable=var8).grid(column = 2, row=8, sticky=W)
var9 = IntVar()
Checkbutton(mainframe, text="Best Before & Batch Information", variable=var9).grid(column = 2, row=9, sticky=W)
var10 = IntVar()
Checkbutton(mainframe, text="Net Weight & Correct Font Size.", variable=var10).grid(column = 2, row=10, sticky=W)
var11 = IntVar()
Checkbutton(mainframe, text="Barcode - Inner", variable=var11).grid(column = 2, row=11, sticky=W)
var12 = IntVar()
Checkbutton(mainframe, text="Address & contact details correct", variable=var12).grid(column = 2, row=12, sticky=W)

def user():
    user_input = os.getlogin()
    tk.Label(mainframe, text = user_input, font='Helvetica 18 bold').grid(row = 0, column = 1)


user()


def save():
    # pyautogui.press('alt')
    # pyautogui.press('printscreen')
    # img = ImageGrab.grabclipboard()
    # img.save('paste.jpg', 'JPEG')

    var_states()


tk.Button(mainframe, text = "Save", command = save).grid(row = 20, column = 1)


root.mainloop()

When I run the code, there will be a dropdown of jpg files. Currently It shows the full directory like so:

I have created a post earlier on how to trim down the path and got something like this:

files = os.listdir("C:/Users/eduards/Desktop/work/data/to-do")
print(files)

But If I use that code above, it will not open the path when clicked open because it doesn't have the full path name.

What I am trying to do is, cut down the path name for display purposes and open the image by following the original full path.

As an example:

The current drop-down menu shows C:/Users/eduards/Desktop/work/data/to-do/img1.jpg My desired result is img1.jpg but in the background open the whole path of above.

Copy comment: this is what I have tried
directory = os.path.splitdrive("C:/Users/eduards/Desktop/work/data/to-do")
choices = glob.glob(os.path.join(directory[1:], "*.jpg"))
, but says
expected str, bytes or os.Pathlike, not tuple. 
Have added [1:] because the path is split into 2 and returning the 2nd part of it.

回答1:

Question: Show only the filename in OptionMenu but get original full path from selection.

Create your own OptionMenu which holds from all images the full path in a dict and shows only the filename as options.

Define your own widget FileNameOptionMenu by inheriting from (tk.OptionMenu)

class FileNameOptionMenu(tk.OptionMenu):
    def __init__(self, parent, directory, extension, callback):

Get from all images the full path and extract the filename.
Save every full path in a dict using the filename as key and the full path as value.

        # Save result from `glob` in a `dict`
        self.glob = {}
        for fpath in glob.glob(os.path.join(directory, "*.{}".format(extension))):
            filename, extension = os.path.splitext(os.path.split(fpath)[1])
            self.glob[filename] = fpath

Define a variable which holds the selected option for later usage.
Init the inherited tk.OptionMenu with the list of the keys from the dict.
Pass the class method self.command as command=.
Save the callback for later usage.

        self.selected = tk.StringVar(parent, 'Select a image...')
        super().__init__(parent, self.selected, *list(self.glob),
                         command=self.command)

        self.callback = callback

This class method get called on every click option selection. On call, it calls the self.callback, which is ImageLabel.configure, with the full path of the selected option.
```
    def command(self, val):
        self.callback(image=self.glob.get(self.selected.get()))
```
Define your own widget ImageLabel by inheriting from (tk.Label).
This class extends the tk.Label.configure to handle .configure(image=<full path> instead of .configure(image=<image object>.
```
class ImageLabel(tk.Label):
    def __init__(self, parent):
        super().__init__(parent, image=None)
```

Overload the inherited class method tk.Label.configure.
Catch the name argument image= and replace the passed full path with a image object.

    def configure(self, **kwargs):
        key = 'image'
        if key in kwargs:
            # Replace the filepath with the image
            fpath = kwargs[key]

            img = Image.open(fpath)
            img = img.resize((240, 250))
            self._image = ImageTk.PhotoImage(img)

            kwargs[key] = self._image

Call the original tk.Label.configure to show the image
```
        super().configure(**kwargs)
```

Usage:

import tkinter as tk
from PIL import Image, ImageTk
import glob, os

class App(tk.Tk):
    def __init__(self):
        super().__init__()

        self.label_image = ImageLabel(parent=self)
        self.label_image.grid(row=2, column=0)

        self.option_menu = \
            FileNameOptionMenu(parent=self,
                               directory='C:/Users/eduards/Desktop/work/data/to-do',
                               extension='jpg',
                               callback=self.label_image.configure
                                               )
        self.option_menu.grid(row=0, column=0)


if __name__ == "__main__":
    App().mainloop()

Tested with Python: 3.5

来源：https://stackoverflow.com/questions/57982864/python-tkinter-cut-down-path-but-open-as-full-directory

标签

python

tkinter

listdir

tkinter.optionmenu