问题
How does a switch statement immediately drop to the correct location in memory? With nested if-statements, it has to perform comparisons with each one, but with a switch statement it goes directly to the correct case. How is this implemented?
回答1:
There are many different ways to compile a switch statement into machine code. Here are a few:
The compiler can produce a series of tests, which is not so inefficient as only about log2(N) tests are enough to dispatch a value among N possible cases.
The compiler can produce a table of values and jump addresses, which in turn will be used by generic lookup code (linear or dichotomic, similar to
bsearch()) and finally jump to the corresponding location.If the case values are dense enough, the compiler can generate a table of jump addresses and code that checks if the switch value is within a range encompassing all case values and jump directly to the corresponding address. This is probably the implementation closest to your description: but with a switch statement it goes directly to the correct case.
Depending on the specific abilities of the target CPU, compiler settings, and the number and distribution of case values, the compiler might use one of the above approaches or another, or a combination of them, or even some other methods.
Compiler designers spend a great deal of effort trying to improve heuristics for these choices. Look at the assembly output or use an online tool such as Godbolt's Compiler Explorer to see various code generation possibilities.
来源：https://stackoverflow.com/questions/42147745/how-switch-statement-works