background Invalid property value in Chrome

问题

I am getting background Invalid property value in Chrome. What am I missing here?

html:

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Email template</title>

</head>
<body style="margin-left: 0; margin-top: 0; margin-right: 0; margin-bottom: 0;">
<div class="t3 sMargin" style="margin-top: 20px; background-color: #dedede; padding-left: 40px; padding-right: 40px; padding-top: 20px; padding-bottom: 20px;">

    <div class="t31" style="color: #5222a8; font-weight: bold; font-size: 20px;">
        Lorem ipsum
    </div>

    <div class="t32" style="background: url( 'data:image/svg+xml;charset=utf8,<svg width='100%' height='100%' viewBox='0 0 20 32' version='1.1' xmlns='http://www.w3.org/2000/svg' xmlns:xlink='http://www.w3.org/1999/xlink' preserveAspectRatio='none'><path fill='none' stroke='#be1196' stroke-width='4' d='M4 10 l5 11 l8 -20'/></svg>'); background-repeat: no-repeat, no-repeat; background-position: 0 0; background-size: 32px 20px; margin-top: 20px; padding-left: 35px; color: #4a4a4a; font-size: 20px;">
        Lorem ipsum
    </div>

    <div class="t32" style="background: url( 'data:image/svg+xml;charset=utf8,<svg width='100%' height='100%' viewBox='0 0 20 32' version='1.1' xmlns='http://www.w3.org/2000/svg' xmlns:xlink='http://www.w3.org/1999/xlink' preserveAspectRatio='none'><path fill='none' stroke='#be1196' stroke-width='4' d='M4 10 l5 11 l8 -20'/></svg>'); background-repeat: no-repeat, no-repeat; background-position: 0 0; background-size: 32px 20px; margin-top: 20px; padding-left: 35px; color: #4a4a4a; font-size: 20px;">
        Lorem ipsum
    </div>

    <div class="t32" style="background: url( 'data:image/svg+xml;charset=utf8,<svg width='100%' height='100%' viewBox='0 0 20 32' version='1.1' xmlns='http://www.w3.org/2000/svg' xmlns:xlink='http://www.w3.org/1999/xlink' preserveAspectRatio='none'><path fill='none' stroke='#be1196' stroke-width='4' d='M4 10 l5 11 l8 -20'/></svg>'); background-repeat: no-repeat, no-repeat; background-position: 0 0; background-size: 32px 20px; margin-top: 20px; padding-left: 35px; color: #4a4a4a; font-size: 20px;">
        Lorem ipsum
    </div>
</div>
</body>

</html>

Since it is an email template I need my styling to be inlined.

As you can see no check mark is displayed (I am drawing it with the help of svg in background).

Here is the jsfiddle.

回答1:

You may want to read first this article: Optimizing SVGs in data URIs. The essence is: whenever you’re using an SVG as a data URI:

Swap its attribute values’ double quotes with single quotes.
Encode <, >, #, any remaining " (like in textual content), non-ASCII characters, and other URL-unsafe characters, like %.
Wrap the URI with double quotes when using it: , url("").

I hope it helps.

.t32{background-image: url("data:image/svg+xml,%3Csvg width='100%25' height='100%25' viewBox='0 0 20 32' version='1.1' xmlns='http://www.w3.org/2000/svg' xmlns:xlink='http://www.w3.org/1999/xlink' preserveAspectRatio='none'%3E%3Cpath fill='none' stroke='%23be1196' stroke-width='4' d='M4 10 l5 11 l8 -20'/%3E%3C/svg%3E");
  background-repeat: no-repeat, no-repeat; 
  background-position: 0 0;  
  background-size: 32px 20px; 
  margin-top: 20px; 
  padding-left: 35px; 
  color: #4a4a4a; 
  font-size: 20px;}

<div class="t3 sMargin" style="margin-top: 20px; background-color: #dedede; padding-left: 40px; padding-right: 40px; padding-top: 20px; padding-bottom: 20px;">

    <div class="t31" style="color: #5222a8; font-weight: bold; font-size: 20px;">
        Lorem ipsum
    </div>

    <div class="t32">
        Lorem ipsum
    </div>

    <div class="t32">
        Lorem ipsum
    </div>

    <div class="t32">
        Lorem ipsum
    </div>
</div>

UPDATE: this time an example with inline CSS.

Please note that I'm using " as a third type of quotes in CSS

<div class="t3 sMargin" style="margin-top: 20px; background-color: #dedede; padding-left: 40px; padding-right: 40px; padding-top: 20px; padding-bottom: 20px;">

    <div class="t31" style="color: #5222a8; font-weight: bold; font-size: 20px;">
        Lorem ipsum
    </div>

    <div class="t32" style="background-image: url(&quot;data:image/svg+xml,%3Csvg width='100%25' height='100%25' viewBox='0 0 20 32' version='1.1' xmlns='http://www.w3.org/2000/svg' xmlns:xlink='http://www.w3.org/1999/xlink' preserveAspectRatio='none'%3E%3Cpath fill='none' stroke='%23be1196' stroke-width='4' d='M4 10 l5 11 l8 -20'/%3E%3C/svg%3E&quot;);background-repeat: no-repeat, no-repeat; background-position: 0 0; background-size: 32px 20px; margin-top: 20px; padding-left: 35px; color: #4a4a4a; font-size: 20px;">
        Lorem ipsum
    </div>

</div>

来源：https://stackoverflow.com/questions/52611039/background-invalid-property-value-in-chrome

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