Powershell Start Process, Wait with Timeout, Kill and Get Exit Code

旧街凉风 提交于 2019-11-27 23:46:14
Martin Brandl

You can terminate the process more simply using $proc | kill or $proc.Kill(). Be aware, that you won't be able to retrieve a exit code in this case, you should rather just update the internal error counter:

for ($i=0; $i -le $max_iterations; $i++)
{
    $proc = Start-Process -filePath $programtorun -ArgumentList $argumentlist -workingdirectory $programtorunpath -PassThru

    # keep track of timeout event
    $timeouted = $null # reset any previously set timeout

    # wait up to x seconds for normal termination
    $proc | Wait-Process -Timeout 4 -ErrorAction SilentlyContinue -ErrorVariable timeouted

    if ($timeouted)
    {
        # terminate the process
        $proc | kill

        # update internal error counter
    }
    elseif ($proc.ExitCode -ne 0)
    {
        # update internal error counter
    }
}
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