Swagger Codegen use existing class

问题

How can I get the swagger codegen to use an existing class instead of creating a new class? Is this possible? For instance I want to use org.springframework.data.domain.Page instead of swagger creating another page class.

回答1:

You could use --import-mappings, as it is explained here:

Sometimes you don't want a model generated. In this case, you can simply specify an import mapping to tell the codegen what not to create. When doing this, every location that references a specific model will refer back to your classes.

You call this on swagger-codegen-cli generate, with the example you included it would be

--import-mappings Page=org.springframework.data.domain.Page

Although importMappings hasn't been included in the general configuration parameters here if you look at the code here you can see it's a List<String>. I haven't used it with the maven plugin but looking at the doc and the code I'm guessing this should work:

<plugin>
    <groupId>io.swagger</groupId>
    <artifactId>swagger-codegen-maven-plugin</artifactId>
    <version>2.2.2-SNAPSHOT</version>
    <executions>
        <execution>
            ...
            <configuration>
                ...
                <importMappings>
                   <importMapping>Page=org.springframework.data.domain.Page</importMapping>
                </importMappings>
            </configuration>
        </execution>
    </executions>
</plugin>

But this was recently changed, so it might be different if you're using an older version of the plugin. Before that changed it seems to be like this:

<plugin>
    <groupId>io.swagger</groupId>
    <artifactId>swagger-codegen-maven-plugin</artifactId>
    <version>2.2.2-SNAPSHOT</version>
    <executions>
        <execution>
            ...
            <configuration>
                ...
                <configOptions>
                   <import-mappings>Page=org.springframework.data.domain.Page;Some=org.example.Some</import-mappings>
                </configOptions>
            </configuration>
        </execution>
    </executions>
</plugin>

According to the comment in that commit the old version should be supported too, but I haven't tried any of this so let me know if it works.

回答2:

None of the answers mentioned here talked about what to add to the swagger yaml file, in case someone is interested this is something that worked for me:

DisplayProperty:  
  type: object
  properties:
    name:
      type: string
    displayName:
      $ref: '#/components/schemas/Text'
    isRequired:
      type: boolean
      example: false
Text:
    type: object

and then have this in the pom

<importMappings>
<importMapping>Text=com.--.--.--.--.Text</importMapping>

回答3:

It's not always possible to use --import-mappings if you have long list of mappings. (At least in case of Windows, which has size-limit for string in command prompt.) That is why better way do it: use mapping with swagger configuration file. (And this option is not fully documented.)

Like that:

java -jar swagger-codegen-cli-2.3.1.jar generate -i myspec.yaml -l java -c myconfig.json

myconfig.json:

{
  "hideGenerationTimestamp": true,
  "dateLibrary": "java8",
  "useRuntimeException": true,
  "modelPackage": "org.my.package.model",
  "apiPackage": "org.my.package.api",
  "importMappings": {
    "Page": "org.springframework.data.domain.Page",
    "MySuperType": "org.my.SuperType"
  }
}

来源：https://stackoverflow.com/questions/44612080/swagger-codegen-use-existing-class

标签

swagger-codegen