问题
How do I make the following work so that helpers's test is run? It doesen't.
def B():
def helper():
"""
>>> some doctest
result
"""
...
if __name__ == "__main__":
import doctest
doctest.testmod()
回答1:
Nested functions cannot be found, because the function object doesn't exist until the B() function is run. You'd have to return it as the result of calling the B() function, then assign it to the __test__ dictionary:
def B()
def helper()
"""
>>> some doctest
result
"""
return helper
# ...
if __name__ == "__main__":
import doctest
__test__ = {'helper': B()}
doctest.testmod()
doctest.testmod() looks for the __test__ global dictionary and looks for docstrings on any classes, methods, functions and modules in the values; any string values are directly executed as docstring tests.
If B() does other things besides, then you probably should make helper() a simple global function instead:
def B():
# uses helper
def helper()
"""
>>> some doctest
result
"""
# ...
if __name__ == "__main__":
import doctest
doctest.testmod()
来源：https://stackoverflow.com/questions/29307730/python3-doctest-helper-internal-functions