Converting yyyy-mm-dd into dd mm yyyy

问题

How to convert 2013-06-24 to 24 Jun 2013? I am using the below code.

date1="2013-06-24";
SimpleDateFormat d= new SimpleDateFormat("dd MMM yyyy");

try{
date2 =  d.parse(date1);
}catch (ParseException e1) {
// TODO Auto-generated catch block
  e1.printStackTrace();
}

But I am getting this error "java.text.ParseException: Unparseable date: "2013-06-24" (at offset 4)"

回答1:

You need two DateFormat instances: One to parse the original String, and another to output the one you want.

DateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd");
DateFormat outputFormat = new SimpleDateFormat("dd MMM yyyy");
String inputDateStr="2013-06-24";
Date date = inputFormat.parse(inputDateStr);
String outputDateStr = outputFormat.format(date);

回答2:

See the first problem is that you are using different delimiters for String and Date. So either you do "2013-06-24" to "2013 06 24" in String or do new SimpleDateFormat("dd MMM yyyy") to new SimpleDateFormat("dd-MMM-yyyy").

And second problem is that you cannot directly change format like this, in String you are having year-month-date format, so first make a Date object with same format than change it to your desired format as below :

date1="2013-06-24";

SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");

Date dt = format.parse(date1);

SimpleDateFormat your_format = new SimpleDateFormat("dd-MMM-yyyy");

date2 = your_format.format(dt);

回答3:

Change

SimpleDateFormat d= new SimpleDateFormat("dd MMM yyyy");

with

SimpleDateFormat d= new SimpleDateFormat("yyyy-MM-dd");

you have to follow the date1 pattern. Then you can format your parsed date with

new SimpleDateFormat("dd MMM yyyy");

回答4:

public String getStringFormatted(String datestring) {
    String format = "dd MM yyyy";
    SimpleDateFormat sdf = new SimpleDateFormat(format, Locale.getDefault());
    return sdf.format(new Date(datestring.replaceAll("-", "/")));
}

回答5:

public String inputFormatget (String datestring1) {
        String format = "dd MM yyyy";
        SimpleDateFormat sdf = new SimpleDateFormat(format, Locale.getDefault());
        return sdf.format(new Date(datestring.replaceAll("-", "/")));
    }

    public String outFormatset (String datestring2) {
        String format = "dd MM yyyy";
        SimpleDateFormat sdf = new SimpleDateFormat(format, Locale.getDefault());
        return sdf.format(new Date(datestring.replaceAll("-", "/")));
    }

回答6:

public static String formateDateFromstring(String inputFormat, String outputFormat, String inputDate){

    Date parsed = null;
    String outputDate = "";

    SimpleDateFormat df_input = new SimpleDateFormat(inputFormat, java.util.Locale.getDefault());
    SimpleDateFormat df_output = new SimpleDateFormat(outputFormat, java.util.Locale.getDefault());

    try {
        parsed = df_input.parse(inputDate);
        outputDate = df_output.format(parsed);

    } catch (ParseException e) {
    }

    return outputDate;

}

String convertedDate = formateDateFromstring(
    "yyyy-MM-dd",
    "dd/MM/yyyy",
    datestring);

updateInsuranceEventFragmentBinding.edtdate.setText(convertedDate);

来源：https://stackoverflow.com/questions/17324060/converting-yyyy-mm-dd-into-dd-mm-yyyy

标签

android

simpledateformat