问题
I am struggling to color full row of rhandsontable in my shiny app based on a cell value.
In the following example, I would like to format full row instead of one cell.
library(rhandsontable)
DF = data.frame(val = 1:10, bool = TRUE, big = LETTERS[1:10],
small = letters[1:10],
dt = seq(from = Sys.Date(), by = "days", length.out = 10),
stringsAsFactors = FALSE)
col_highlight = 2
row_highlight = c(5, 7)
rhandsontable(DF, width = 550, height = 300) %>%
hot_cols(renderer = "
function (instance, td, row, col, prop, value, cellProperties) {
Handsontable.renderers.TextRenderer.apply(this, arguments);
if(value == 'F' | value == 'f') {
td.style.background = 'pink';
} else if(value == 'J' | value == 'j') {
td.style.background = 'lightgreen';
} else if(value == 'X' | value == 'x') {
td.style.background = 'lightblue'}
}")
回答1:
The idea of renderer is that applied to all cells separately, so at the same time cell value can't be a 'F' and 'f'. For every row you have to select column 2 to check if value is 'F' and select column 3 to check if value is 'f'.
rhandsontable(DF, width = 550, height = 300) %>%
hot_cols(renderer = "
function (instance, td, row, col, prop, value, cellProperties) {
Handsontable.renderers.TextRenderer.apply(this, arguments);
if(instance.getData()[row][2] == 'F' | instance.getData()[row][3] == 'f'){
td.style.background = 'pink';
} else if(instance.getData()[row][2] == 'J' | instance.getData()[row][3] == 'j') {
td.style.background = 'lightgreen';
} else if(instance.getData()[row][2] == 'X' | instance.getData()[row][3] == 'x') {
td.style.background = 'lightblue'
}
}")
来源:https://stackoverflow.com/questions/45602317/color-row-based-on-cell-value-in-rhandsontable