How can we get weekday based on given date in unix

问题

From a given date in %m-%d-%Y format we should determine what day it is Please help me with the command

like if i pass a date like 09-01-2017 output should be Friday

回答1:

DayOfWeek=$(date +%A)

This would yield the day of week monday-sunday If your input date is strictly in the format MM-DD-YYYY, use the following

IFS='-' read -ra ADDR <<< "09-01-2017"
formattedDate=${ADDR[2]}-${ADDR[0]}-${ADDR[1]}
date -d  $formattedDate +%A

The first line tokenizes the components of the date and the second rearranges them

回答2:

If you have your date like this:

d="09-01-2017"

you need to reformat it to "YYYY-MM-DD"

date -d $(echo $d|awk -F- '{print $3 "-" $1 "-" $2}') +%A # DOW 

回答3:

Very simple. Just use the date command itself with correct options.

$ date -j -f '%m-%d-%Y' "09-01-2017" +'%A'
Friday

来源：https://stackoverflow.com/questions/46024251/how-can-we-get-weekday-based-on-given-date-in-unix