问题
I need to check if a given date falls in the current month, and I wrote the following code, but the IDE reminded me that the getMonth() and getYear() methods are obsolete. I was wondering how to do the same thing in newer Java 7 or Java 8.
private boolean inCurrentMonth(Date givenDate) {
Date today = new Date();
return givenDate.getMonth() == today.getMonth() && givenDate.getYear() == today.getYear();
}
回答1:
Time Zone
The other answers ignore the crucial issue of time zone. A new day dawns earlier in Paris than in Montréal. So at the same simultaneous moment, the dates are different, "tomorrow" in Paris while "yesterday" in Montréal.
Joda-Time
The java.util.Date and .Calendar classes bundled with Java are notoriously troublesome, confusing, and flawed. Avoid them.
Instead use either Joda-Time library or the java.time package in Java 8 (inspired by Joda-Time).
Here is example code in Joda-Time 2.5.
DateTimeZone zone = DateTimeZone.forID( "America/Montreal" );
DateTime dateTime = new DateTime( yourJUDate, zone ); // Convert java.util.Date to Joda-Time, and assign time zone to adjust.
DateTime now = DateTime.now( zone );
// Now see if the month and year match.
if ( ( dateTime.getMonthOfYear() == now.getMonthOfYear() ) && ( dateTime.getYear() == now.getYear() ) ) {
// You have a hit.
}
For a more general solution to see if a moment falls within any span of time (not just a month), search StackOverflow for "joda" and "interval" and "contain".
回答2:
//Create 2 instances of Calendar
Calendar cal1 = Calendar.getInstance();
Calendar cal2 = Calendar.getInstance();
//set the given date in one of the instance and current date in the other
cal1.setTime(givenDate);
cal2.setTime(new Date());
//now compare the dates using methods on Calendar
if(cal1.get(Calendar.YEAR) == cal2.get(Calendar.YEAR)) {
if(cal1.get(Calendar.MONTH) == cal2.get(Calendar.MONTH)) {
// the date falls in current month
}
}
回答3:
java.time (Java 8)
There are several ways to do it with the new java.time API (tutorial). You can do it using .get(ChronoField.XY)
, but I think this is prettier:
Instant given = givenDate.toInstant();
Instant ref = Instant.now();
return Month.from(given) == Month.from(ref) && Year.from(given).equals(Year.from(ref));
For better re-usability you can also refactor this code to "temporal query":
public class TemporalQueries {
//TemporalQuery<R> { R queryFrom(TemporalAccessor temporal) }
public static Boolean isCurrentMonth(TemporalAccessor temporal) {
Instant ref = Instant.now();
return Month.from(temporal) == Month.from(ref) && Year.from(temporal).equals(Year.from(ref));
}
}
Boolean result = givenDate.toInstant().query(TemporalQueries::isCurrentMonth); //Lambda using method reference
回答4:
As far as I know the Calendar class and all derived from it return the date using the get(). See the documentation for this class. Also here is an example taken from here:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy MMM dd HH:mm:ss");
Calendar calendar = new GregorianCalendar(2013,1,28,13,24,56);
int year = calendar.get(Calendar.YEAR);
int month = calendar.get(Calendar.MONTH); // Jan = 0, dec = 11
int dayOfMonth = calendar.get(Calendar.DAY_OF_MONTH);
int dayOfWeek = calendar.get(Calendar.DAY_OF_WEEK);
int weekOfYear = calendar.get(Calendar.WEEK_OF_YEAR);
int weekOfMonth= calendar.get(Calendar.WEEK_OF_MONTH);
int hour = calendar.get(Calendar.HOUR); // 12 hour clock
int hourOfDay = calendar.get(Calendar.HOUR_OF_DAY); // 24 hour clock
int minute = calendar.get(Calendar.MINUTE);
int second = calendar.get(Calendar.SECOND);
int millisecond= calendar.get(Calendar.MILLISECOND);
System.out.println(sdf.format(calendar.getTime()));
System.out.println("year \t\t: " + year);
System.out.println("month \t\t: " + month);
System.out.println("dayOfMonth \t: " + dayOfMonth);
System.out.println("dayOfWeek \t: " + dayOfWeek);
System.out.println("weekOfYear \t: " + weekOfYear);
System.out.println("weekOfMonth \t: " + weekOfMonth);
System.out.println("hour \t\t: " + hour);
System.out.println("hourOfDay \t: " + hourOfDay);
System.out.println("minute \t\t: " + minute);
System.out.println("second \t\t: " + second);
System.out.println("millisecond \t: " + millisecond);
which outputs
2013 Feb 28 13:24:56
year : 2013
month : 1
dayOfMonth : 28
dayOfWeek : 5
weekOfYear : 9
weekOfMonth : 5
hour : 1
hourOfDay : 13
minute : 24
second : 56
millisecond : 0
I think it was replaced because the new way offers a much simpler handling using a single function, which is much easier to remember.
回答5:
java.time (Java 8)
Java 8 provides the YearMonth class which represents a given month within a given year (e.g. January 2018). This can be used to compare against the YearMonth
of the given date.
private boolean inCurrentMonth(Date givenDate) {
ZoneId timeZone = ZoneOffset.UTC; // Use whichever time zone makes sense for your use case
LocalDateTime givenLocalDateTime = LocalDateTime.ofInstant(givenDate.toInstant(), timeZone);
YearMonth currentMonth = YearMonth.now(timeZone);
return currentMonth.equals(YearMonth.from(givenLocalDateTime));
}
Note that this approach will work for any of the Java 8 time classes that have both a month and a date part (LocalDate
, ZonedDateTime
, etc.) and not just LocalDateTime
.
来源:https://stackoverflow.com/questions/26824020/java-check-if-a-given-date-is-within-current-month