问题
Is there a way in .NET, using Reflection.Emit
, to access the topmost-but-one item from the stack? So if A is topmost, and B next - I want to process B then A. It would be fine to duplicate B above A (since I can simply "pop" the second B when I get to it).
Currently, I am declaring a local:
LocalBuilder loc = il.DeclareLocal(typeof(Foo));
il.Emit(OpCodes.Stloc, loc); // store and pop topmost stack item
// work with (pop) previous stack item
il.Emit(OpCodes.Ldloc, loc); // push old topmost stack item
Is there a route that doesn't need the explicit local?
回答1:
I don't think so. In IL there aren't any instructions like swap which would allow you to do what you want. Why do you see using a local as objectionable? If the JIT compiler is good enough this won't result in any slower machine code than using a hypothetical swap operation in IL.
回答2:
+1 for kvbs answer, see: http://www.codeproject.com/KB/msil/msilenhancement.aspx
回答3:
Inline with what kvb said, you could try a small function to do some reordering. Not sure if it would be any faster.
回答4:
I encountered this same problem. I wanted to generate a rather large method and I often wanted to 'swap' in order to store a calculated value. I was unhappy with the large volume of locals showing up in ildasm and noticed that BeginScope/EndScope wasn't any help. I wound up creating a local 'swap' for the context of my method and reusing it for every swap operation. It makes the generated IL cleaner; not sure if it has any meaningful impact on performance.
来源:https://stackoverflow.com/questions/718003/reflection-emit-access-topmost-but-one-item-from-stack