Overriding “Variables not shown” in dplyr, to display all columns from df

耗尽温柔 提交于 2020-01-30 14:30:31

问题


When I have a column in a local data frame, sometimes I get the message Variables not shown such as this (ridiculous) example just needed enough columns.

library(dplyr)
library(ggplot2) # for movies

movies %.% 
 group_by(year) %.% 
 summarise(Length = mean(length), Title = max(title), 
  Dramaz = sum(Drama), Actionz = sum(Action), 
  Action = sum(Action), Comedyz = sum(Comedy)) %.% 
 mutate(Year1 = year + 1)

   year    Length                       Title Dramaz Actionz Action Comedyz
1  1898  1.000000 Pack Train at Chilkoot Pass      1       0      0       2
2  1894  1.000000           Sioux Ghost Dance      0       0      0       0
3  1902  3.555556     Voyage dans la lune, Le      1       0      0       2
4  1893  1.000000            Blacksmith Scene      0       0      0       0
5  1912 24.382353            Unseen Enemy, An     22       0      0       4
6  1922 74.192308      Trapped by the Mormons     20       0      0      16
7  1895  1.000000                 Photographe      0       0      0       0
8  1909  9.266667              What Drink Did     14       0      0       7
9  1900  1.437500      Uncle Josh's Nightmare      2       0      0       5
10 1919 53.461538     When the Clouds Roll by     17       2      2      29
..  ...       ...                         ...    ...     ...    ...     ...
Variables not shown: Year1 (dbl)

I want to see Year1! How do I see all the columns, preferably by default.


回答1:


There's (now) a way of overriding the width of columns that gets printed out. If you run this command all will be well

options(dplyr.width = Inf)

I wrote it up here.




回答2:


You might like glimpse :

> movies %>%
+  group_by(year) %>%
+  summarise(Length = mean(length), Title = max(title),
+   Dramaz = sum(Drama), Actionz = sum(Action),
+   Action = sum(Action), Comedyz = sum(Comedy)) %>%
+  mutate(Year1 = year + 1) %>% glimpse()
Variables:
$ year    (int) 1893, 1894, 1895, 1896, 1897, 1898, 1899, 1900, 1901, 1902,...
$ Length  (dbl) 1.000000, 1.000000, 1.000000, 1.307692, 1.000000, 1.000000,...
$ Title   (chr) "Blacksmith Scene", "Sioux Ghost Dance", "Photographe", "Ve...
$ Dramaz  (int) 0, 0, 0, 1, 0, 1, 2, 2, 5, 1, 2, 3, 4, 5, 1, 8, 14, 14, 14,...
$ Actionz (int) 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 3, 0, 0, 0, 0, 3, 0, 0, 1, 0,...
$ Action  (int) 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 3, 0, 0, 0, 0, 3, 0, 0, 1, 0,...
$ Comedyz (int) 0, 0, 0, 1, 2, 2, 1, 5, 8, 2, 8, 10, 6, 2, 6, 8, 7, 2, 2, 4...
$ Year1   (dbl) 1894, 1895, 1896, 1897, 1898, 1899, 1900, 1901, 1902, 1903,...NULL



回答3:


dplyr has its own printing functions for dplyr objects. In this case, the object that is the result of your operation is tbl_df. The matching print function is then dplyr:::print.tbl_df. This reveals that trunc_mat is the function responsible for what is printed and not, including which variables.

Sadly, dplyr:::print.tbl_df does not pass on any parameters to trunc_mat and trunc_mat also does not support choosing which variables are shown (only how many rows). A workaround is to cast the result of dplyr to a data.frame and use head:

res = movies %.% 
 group_by(year) %.% 
 summarise(Length = mean(length), Title = max(title), 
  Dramaz = sum(Drama), Actionz = sum(Action), 
  Action = sum(Action), Comedyz = sum(Comedy)) %.% 
 mutate(Year1 = year + 1)

head(data.frame(res))
  year    Length                       Title Dramaz Actionz Action Comedyz
1 1898  1.000000 Pack Train at Chilkoot Pass      1       0      0       2
2 1894  1.000000           Sioux Ghost Dance      0       0      0       0
3 1902  3.555556     Voyage dans la lune, Le      1       0      0       2
4 1893  1.000000            Blacksmith Scene      0       0      0       0
5 1912 24.382353            Unseen Enemy, An     22       0      0       4
6 1922 74.192308      Trapped by the Mormons     20       0      0      16
  Year1
1  1899
2  1895
3  1903
4  1894
5  1913
6  1923



回答4:


So, this is a bit old, but I found this when looking for answers to same problem. I came up with this solution that holds to the spirit of piping but identical in function to the accepted answer (note that the pipe symbol %.% is deprecated in favor of %>%)

movies %>% 
    group_by(year) %>% 
    summarise(Length = mean(length), Title = max(title), 
    Dramaz = sum(Drama), Actionz = sum(Action), 
    Action = sum(Action), Comedyz = sum(Comedy)) %>% 
    mutate(Year1 = year + 1) %>%
    as.data.frame %>%
    head



回答5:


movies %.% group_by(year) %.% ....... %.% print.default

dplyr uses, instead of the default print option,dplyr:::print.tbl_df to make sure your screen doesn't overload with huge data-sets. When you've finally whittled your stuff down to what you want and don't want to be saved from your own mistakes anymore, just stick print.default on the end to spit out everything.


BTW, methods(print) shows how many packages need to write their own print functions (think about, eg, igraph or xts --- these are new data-types so you need to tell them how to be displayed on the screen).

HTH the next googler.



来源:https://stackoverflow.com/questions/22471256/overriding-variables-not-shown-in-dplyr-to-display-all-columns-from-df

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!