Bus error with allocated memory on a heap

问题

I have Bus Error in such code:

char* mem_original;
int int_var = 987411;
mem_original = new char [250];
memcpy(&mem_original[250-sizeof(int)], &int_var, sizeof(int));
...
const unsigned char* mem_u_const = (unsigned char*)mem_original;
...
const unsigned char *location = mem_u_const + 250 - sizeof(int);

std::cout << "sizeof(int) = " << sizeof(int) << std::endl;//it's printed out as 4
std::cout << "byte 0 = " << int(*location) << std::endl;
std::cout << "byte 1 = " << int(*(location+1)) << std::endl;
std::cout << "byte 2 = " << int(*(location+2)) << std::endl;
std::cout << "byte 3 = " << int(*(location+3)) << std::endl;
int original_var = *((const int*)location);
std::cout << "original_var = " << original_var << std::endl;

That works well few times, printing out:

sizeof(int) = 4
byte 0 = 0
byte 1 = 15
byte 2 = 17
byte 3 = 19
original_var = 987411

And then it fails with:

sizeof(int) = 4
byte 0 = 0
byte 1 = 15
byte 2 = 17
byte 3 = 19
Bus Error

It's built & run on Solaris OS (C++ 5.12) Same code on Linux (gcc 4.12) & Windows (msvc-9.0) is working well.

We can see:

memory was allocated on the heap by new[].
memory is accessible (we can read it byte by byte)
memory contains exactly what there should be, not corrupted.

So what may be reason for Bus Error? Where should I look?

UPD: If I memcpy(...) location in the end to original_var, it works. But what the problem in *((const int*)location) ?

回答1:

This is a common issue for developers with no experience on hardware that has alignment restrictions - such as SPARC. x86 hardware is very forgiving of misaligned access, albeit with performance impacts. Other types of hardware? SIGBUS.

This line of code:

int original_var = *((const int*)location);

invokes undefined behavior. You're taking an unsigned char * and interpreting what it points to as an int. You can't do that safely. Period. It's undefined behavior - for the very reason you're experiencing.

You're violating the strict aliasing rule. See What is the strict aliasing rule? Put simply, you can't refer to an object of one type as another type. A char * does not and can not refer to an int.

Oracle's Solaris Studio compilers actually provide a command-line argument that will let you get away with that on SPARC hardware - -xmemalign=1i (see https://docs.oracle.com/cd/E19205-01/819-5265/bjavc/index.html). Although to be fair to GCC, without that option, the forcing you do in your code will still SIGBUS under the Studio compiler.

Or, as you've already noted, you can use memcpy() to copy bytes around no matter what they are - as long as you know the source object is safe to copy into the target object - yes, there are cases when that's not true.

回答2:

I get the following warning when I compile your code:

main.cpp:19:26: warning: cast from 'const unsigned char *' to 'const int *' increases required alignment from 1 to 4 [-Wcast-align]
    int original_var = *((const int*)location);
                         ^~~~~~~~~~~~~~~~~~~~

This seems to be the cause of the bus error, because improperly aligned access can cause a bus error.

回答3:

Although I don’t have access to a SPARC right now to test this, I’m pretty sure from my experiences on that platform that this line is your problem:

const unsigned char *location = mem_u_const + 250 - sizeof(int);

The mem_u_const block was originally allocated by new for an array of characters. Since sizeof(unsigned char) is 1 and sizeof(int) is 4, you are adding 246 bytes. This is not a multiple of 4.

On SPARC, the CPU can only read 4-byte words if they are aligned to 4-byte boundaries. Your attempt to read a misaligned word is what causes the bus error.

I recommend allocating a struct with an array of unsigned char followed by an int, rather than a bunch of pointer math and casts like the one that caused this bug.

来源：https://stackoverflow.com/questions/42630843/bus-error-with-allocated-memory-on-a-heap

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c++

solaris

bus-error