问题
I want to remove duplicates from nsmutablearray.
Array Structure :-
( { "act_end_date" = ""; "act_entry_date" = "13/11/2014"; "act_recurrrance_type" = Daily; "act_start_date" = "2014-11-13"; "row_id" = 0; "act_id" = 2; } { "act_end_date" = ""; "act_entry_date" = "13/11/2014"; "act_recurrrance_type" = Daily; "act_start_date" = "2014-11-13"; "row_id" = 1; "act_id" = 2; } { "act_end_date" = ""; "act_entry_date" = "16/11/2014"; "act_recurrrance_type" = Daily1; "act_start_date" = "2014-11-15"; "row_id" = 2; "act_id" = 3; } )
What I want is to check where array contain any dictionary which have same act_id. If yes then remove 1st dictionary. i.e the expected result for the above arrayis :-
(
{
"act_end_date" = "";
"act_entry_date" = "13/11/2014";
"act_recurrrance_type" = Daily;
"act_start_date" = "2014-11-13";
"row_id" = 1;
"act_id" = 2;
}
{
"act_end_date" = "";
"act_entry_date" = "16/11/2014";
"act_recurrrance_type" = Daily1;
"act_start_date" = "2014-11-15";
"row_id" = 2;
"act_id" = 3;
}
)
Is their any way? Is it possible by using NSPREDICATE?
I Tries to do it in below way :-
NSMutableArray *filteredArray = [NSMutableArray array];
for (NSMutableDictionary* E1 in Event_Array)
{
BOOL hasDuplicate = [[filteredArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"act_id == %@", [E1 objectForKey:@"act_id"]]] count] > 0;
if (!hasDuplicate)
{
[filteredArray addObject:E1];
}
}
For it returns array :---
(
{
"act_end_date" = "";
"act_entry_date" = "13/11/2014";
"act_recurrrance_type" = Daily;
"act_start_date" = "2014-11-13";
"row_id" = 0;
"act_id" = 2;
}
)
What i want is
(
{
"act_end_date" = "";
"act_entry_date" = "13/11/2014";
"act_recurrrance_type" = Daily;
"act_start_date" = "2014-11-13";
"row_id" = 1;
"act_id" = 2;
}
)
回答1:
Assuming you want the latest object to be in the list.
Solution 1: (Simple)
Reverse your array
NSMutableArray *filteredArray = [NSMutableArray array];
for (int i = Event_Array.count-1; i>= 0; i--)
{
NSMutableDictionary* E1 = [Event_Array objectAtIndex:i];
BOOL hasDuplicate = [[filteredArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"act_id == %@", [E1 objectForKey:@"act_id"]]] count] > 0;
if (!hasDuplicate)
{
[filteredArray addObject:E1];
}
}
Solution 2:
Use NSMutableDictionary instead of array.
//Keys are act_id(s) "2" = { "act_end_date" = ""; "act_entry_date" = "13/11/2014"; "act_recurrrance_type" = Daily; "act_start_date" = "2014-11-13"; "row_id" = 1; "act_id" = 2; }; "3" = { "act_end_date" = ""; "act_entry_date" = "16/11/2014"; "act_recurrrance_type" = Daily1; "act_start_date" = "2014-11-15"; "row_id" = 2; "act_id" = 3; }
回答2:
NSMutableSet *keysSet = [[NSMutableSet alloc] init];
NSMutableArray *filteredArray = [[NSMutableArray alloc]init];
for (NSDictionary *msg in germanMakes) {
NSString *key = [NSString stringWithFormat:@"%@", msg[@"act_id"]];
if (![keysSet containsObject:key]) {
[filteredArray addObject:msg];
[keysSet addObject:key];
}
}
NSLog(@"filteredResults %@ keyset%@",filteredArray , keysSet);
germanMakes is your initial array, keysSet contains unique act_id (e.g. 1,2,3,4..), filteredArray is your array filtered by act_id. Keep in mind this does not get sorted ascending, but that part will be easy.
来源:https://stackoverflow.com/questions/26904295/remove-duplicate-from-nsmutablearray-containing-nsdictionary