Django handler500 as a Class Based View

问题

Why does this not work

handler500 = TemplateView.as_view(template_name="500.html")

I get the following exception:

Traceback (most recent call last):
  File "/usr/lib/python2.6/wsgiref/handlers.py", line 94, in run    
    self.finish_response()
  File "/usr/lib/python2.6/wsgiref/handlers.py", line 134, in finish_response
    for data in self.result:
  File "/home/hatem/projects/leadsift_app/.virtualenv/lib/python2.6/site-packages/django/template/response.py", line 117, in __iter__
    raise ContentNotRenderedError('The response content must be 'ContentNotRenderedError: The response content must be rendered before it can be iterated over.

I found this set of notes that describe that you are shooting yourself in the foot to use class based views there, why is that?

EDIT: I have ended up using this ... but I am still hoping someone out there would tell me how to get the original oneliner or similar working

class Handler500(TemplateView):
    template_name = "500.html"  
    @classmethod
    def as_error_view(cls):
        v = cls.as_view()
        def view(request):
            r = v(request)
            r.render()
            return r
        return view
handler500 = Handler500.as_error_view()

回答1:

I would rather just use stock 500 templates with static HTML in vanilla Django then do anything with code. This is one toggle I believe should not be touched.

回答2:

I think its actually quite simple (in Django 1.7 with Python 3.4):

views.py

from django.http import HttpResponse
from django.views.generic.base import View

class Custom500View(View):
    def dispatch(self, request, *args, **kwargs):
        return HttpResponse('My custom django 500 page')

urls.py

from .views import Custom500View

handler500 = Custom500View.as_view()

来源：https://stackoverflow.com/questions/13633508/django-handler500-as-a-class-based-view