antlr4 can't extract literal into token

问题

I have the following grammar and am trying to start out slowly, working up to move complex arguments.

grammar Command;

commands : command+ EOF; 
command : NAME args NL;
args : arg | ;

arg : DASH LOWER | LOWER;
//arg : DASH 'a' | 'x';

NAME : [_a-zA-Z0-9]+;
NL : '\n';
WS : [ \t\r]+ -> skip ; // spaces, tabs, newlines
DASH : '-';
LOWER: [a-z];//'a' .. 'z';

I was hoping (for now) to parse files like this:

cmd1
cmd3 -a

If I run that input through grun I get an error:

$ java org.antlr.v4.gui.TestRig Command commands -tree
...
`line 3:6 mismatched input 'a' expecting LOWER`

It seems like LOWER should match 'a'. If I change the arg definition to be the commented out line it works fine and I get the '-a' as an arg. What's the difference between using LOWER and using a 'a' explicitly?

回答1:

As soon as you have a "mismatched" error, add -tokens to grun to display the tokens, it helps finding the discrepancy between what you THINK the lexer will do and what it actually DOES. With your grammar :

$ alias grun='java org.antlr.v4.gui.TestRig'
$ grun Command commands -tokens -diagnostics t.text
[@0,0:3='cmd1',<NAME>,1:0]
[@1,4:4='\n',<'
'>,1:4]
[@2,5:8='cmd3',<NAME>,2:0]
[@3,10:10='-',<'-'>,2:5]
[@4,11:11='a',<NAME>,2:6]
[@5,12:12='\n',<'
'>,2:7]
[@6,13:12='<EOF>',<EOF>,3:0]
line 2:6 mismatched input 'a' expecting LOWER

you immediately see that the letter a is a NAMEand not the expected LOWER.

Also watch rules with an empty alternative :

args
    :   arg
    |
    ;

may lead to problems in some circumstances. I prefer to explicitly add the ? suffix which means zero or one time. So my solution would be :

grammar Command;

commands
@init {System.out.println("Question last update 1829");}
    :   command+ EOF
    ; 

command
    :   NAME args? NL
    ;

args
    :   arg
    ;

arg : DASH? LOWER ;

LOWER : [a-z] ;
NAME  : [_a-zA-Z0-9]+;
DASH  : '-' ;
NL    : '\n' ;
WS    : [ \t\r]+ -> skip ;

Execution :

$ grun Command commands -tokens -diagnostics t.text
[@0,0:3='cmd1',<NAME>,1:0]
[@1,4:4='\n',<'
'>,1:4]
[@2,5:8='cmd3',<NAME>,2:0]
[@3,10:10='-',<'-'>,2:5]
[@4,11:11='a',<LOWER>,2:6]
[@5,12:12='\n',<'
'>,2:7]
[@6,13:12='<EOF>',<EOF>,3:0]
Question last update 1829

来源：https://stackoverflow.com/questions/46527648/antlr4-cant-extract-literal-into-token

标签

antlr4

lexer