问题
Well I have weird problem. I can't create a zombie process in my project, but I can do this in other file. There's simple instructions:
int main()
{
if(fork()==0)
printf("Some instructions\n");
else
{
sleep(10);
wait(0);
}
return 0;
}
That simple code create a zombie process for 10 seconds. I'm checking and it actually exists.
But if I copy this code to my program (my own shell), everything executing like before BUT zombie process doesn't exist at all. I don't know what's the difference. It's same code.
Is there a more information I should know about that? Is there a other way to create zombie in simple way?
回答1:
Try this python script:
#!/usr/bin/python
# -*- coding: utf8 -*-
import subprocess
import time
import threading
# Create 100 subprocesses
proc = {}
for i in xrange(0,1000):
proc[i] = subprocess.Popen(['ls','-l'])
# create zombies from this processes, observe one minute zombies
time.sleep(60)
# Zombies dead
proc.communicate()
time.sleep(5)
Thereafter check zombies:
# ps -A | grep defunc
14711 pts/49 00:00:00 ls <defunct>
14713 pts/49 00:00:00 ls <defunct>
14716 pts/49 00:00:00 ls <defunct>
....
14740 pts/49 00:00:00 ls <defunct>
14741 pts/49 00:00:00 ls <defunct>
14742 pts/49 00:00:00 ls <defunct>
14743 pts/49 00:00:00 ls <defunct>
14746 pts/49 00:00:00 ls <defunct>
14749 pts/49 00:00:00 ls <defunct>
....
14805 pts/49 00:00:00 ls <defunct>
14806 pts/49 00:00:00 ls <defunct>
Or C:
#include <stdlib.h>
#include <sys/types.h>
#include <unistd.h>
int main ()
{
pid_t child_pid;
child_pid = fork ();
if (child_pid > 0) {
sleep (60);
}
else {
exit (0);
}
return 0;
}
Should work like a charm, like a crystal clear pure Haitian Vodou.
来源:https://stackoverflow.com/questions/13647519/cant-create-zombie-process-in-linux