问题
I am trying to use Shapely's within
function to do a 'spatial join' of a LineString and a Point file (FYI, the point file was generated using the interpolate
function on the LineString
). Problem is - nothing is being returned.
# this condition is never satisfied
if point.within(line):
# here I write stuff to a file
where:
point = POINT (-9763788.9782693591000000 5488878.3678984242000000)
line = LINESTRING (-9765787.998118492 5488940.974948905, -9748582.801636808 5488402.127570709)
What am I missing?
回答1:
There are floating point precision errors when finding a point on a line. Use the distance with an appropriate threshold instead.
from shapely.geometry import Point, LineString
line = LineString([(-9765787.9981184918, 5488940.9749489054), (-9748582.8016368076, 5488402.1275707092)])
point = Point(-9763788.9782693591, 5488878.3678984242)
line.within(point) # False
line.distance(point) # 7.765244949417793e-11
line.distance(point) < 1e-8 # True
来源:https://stackoverflow.com/questions/21291725/determine-if-shapely-point-is-within-a-linestring-multilinestring