问题
I have the following Scala class:
class Person(var name : String, var age : Int, var email : String)
I would like to use the Person constructor as a curried function:
def mkPerson = (n : String) => (a : Int) => (e : String) => new Person(n,a,e)
This works, but is there another way to accomplish this? This approach seems a bit tedious and error-prone. I could imagine something like Function.curried, but then for constructors.
回答1:
This will work:
def mkPerson = (new Person(_, _, _)).curried
回答2:
A bit late to this party, but if you make Person a case class:
scala> case class Person(name: String, age: Int, email: String)
defined class Person
Scala generates a companion object containing Person.apply(String, Int, String) and some other stuff for you. Then you can do:
scala> Person.curried
res5: String => (Int => (String => Person)) = <function1>
Which is shorthand for:
(Person.apply _).curried
It works with var parameters too.
回答3:
may be so:
val mkPerson = Function.curried((n: String,a:Int,e:String) => new Person (n,a,e))来源：https://stackoverflow.com/questions/3862717/scala-curried-constructors