currying

Unexpected behavior of bound function

折月煮酒 提交于 2021-02-10 20:37:49
问题 Tried to create a function mapping numeric characters (i.e. '0' to '9') to true and other characters to false : const isNumeric = String.prototype.includes.bind('0123456789'); isNumeric('1') and isNumeric('0') returned true . Expected ['1', '0'].every(isNumeric) to be true too but it turned out to be false. Something I'm missing? This was on node v10.16.3 回答1: includes has a second parameter called position which is the position within the string at which to begin searching. every , like

Unexpected behavior of bound function

和自甴很熟 提交于 2021-02-10 20:34:43
问题 Tried to create a function mapping numeric characters (i.e. '0' to '9') to true and other characters to false : const isNumeric = String.prototype.includes.bind('0123456789'); isNumeric('1') and isNumeric('0') returned true . Expected ['1', '0'].every(isNumeric) to be true too but it turned out to be false. Something I'm missing? This was on node v10.16.3 回答1: includes has a second parameter called position which is the position within the string at which to begin searching. every , like

Why is it fair to think of just locally small cartesian closed categories in Haskell for the Curry class?

元气小坏坏 提交于 2021-02-07 19:14:41
问题 Control.Category.Constrained is a very interesting project that presents the class for cartesian closed categories - Curry. Yet, I do not see why we think of all cartesian closed categories which allow curry and uncurry ( Hom(X * Y, Z) ≅ Hom(X, Z^Y) in terms of category theory). Wikipedia says that such property holds only for locally small cartesian closed categories. Under this post many people suggest that Hask itself is not locally small (on the other hand, everyone says that Hask is not

Why is it fair to think of just locally small cartesian closed categories in Haskell for the Curry class?

泪湿孤枕 提交于 2021-02-07 19:13:55
问题 Control.Category.Constrained is a very interesting project that presents the class for cartesian closed categories - Curry. Yet, I do not see why we think of all cartesian closed categories which allow curry and uncurry ( Hom(X * Y, Z) ≅ Hom(X, Z^Y) in terms of category theory). Wikipedia says that such property holds only for locally small cartesian closed categories. Under this post many people suggest that Hask itself is not locally small (on the other hand, everyone says that Hask is not

Curried function in scala

泄露秘密 提交于 2021-02-07 07:14:20
问题 I have a definition of next methods: def add1(x: Int, y: Int) = x + y def add2(x: Int)(y: Int) = x + y the second one is curried version of first one. Then if I want to partially apply second function I have to write val res2 = add2(2) _ . Everything is fine. Next I want add1 function to be curried. I write val curriedAdd = (add1 _).curried Am I right that curriedAdd is similiar to add2 ? But when I try to partially apply curriedAdd in a such way val resCurried = curriedAdd(4) _ I get a

Curried function in scala

[亡魂溺海] 提交于 2021-02-07 07:12:17
问题 I have a definition of next methods: def add1(x: Int, y: Int) = x + y def add2(x: Int)(y: Int) = x + y the second one is curried version of first one. Then if I want to partially apply second function I have to write val res2 = add2(2) _ . Everything is fine. Next I want add1 function to be curried. I write val curriedAdd = (add1 _).curried Am I right that curriedAdd is similiar to add2 ? But when I try to partially apply curriedAdd in a such way val resCurried = curriedAdd(4) _ I get a

Curried function in scala

|▌冷眼眸甩不掉的悲伤 提交于 2021-02-07 07:11:38
问题 I have a definition of next methods: def add1(x: Int, y: Int) = x + y def add2(x: Int)(y: Int) = x + y the second one is curried version of first one. Then if I want to partially apply second function I have to write val res2 = add2(2) _ . Everything is fine. Next I want add1 function to be curried. I write val curriedAdd = (add1 _).curried Am I right that curriedAdd is similiar to add2 ? But when I try to partially apply curriedAdd in a such way val resCurried = curriedAdd(4) _ I get a

Curried function in scala

南楼画角 提交于 2021-02-07 07:09:22
问题 I have a definition of next methods: def add1(x: Int, y: Int) = x + y def add2(x: Int)(y: Int) = x + y the second one is curried version of first one. Then if I want to partially apply second function I have to write val res2 = add2(2) _ . Everything is fine. Next I want add1 function to be curried. I write val curriedAdd = (add1 _).curried Am I right that curriedAdd is similiar to add2 ? But when I try to partially apply curriedAdd in a such way val resCurried = curriedAdd(4) _ I get a

Function application for curried functions in JavaScript and ES6

╄→гoц情女王★ 提交于 2021-02-05 08:35:24
问题 I love that ECMAScript 6 allows you to write curried functions like this: var add = x => y => z => x + y + z; However, I hate that we need to parenthesize every argument of a curried function: add(2)(3)(5); I want to be able to apply curried functions to multiple arguments at once: add(2, 3, 5); What should I do? I don't care about performance. 回答1: Currying and the application of curried functions are controversial issues in Javascript. In simple terms, there are two opposing views, which I

How to correctly serialize Javascript curried arrow functions?

懵懂的女人 提交于 2021-01-27 06:20:11
问题 const makeIncrementer = s=>a=>a+s makeIncrementer(10).toString() // Prints 'a=>a+s' which would make it impossible to de-serialize correctly (I would expect something like a=>a+10 instead. Is there a way to do it right? 回答1: This is a great question. While I don't have a perfect answer, one way you could get details about the argument/s is to create a builder function that stores the necessary details for you. Unfortunately I can't figure out a way to know which internal variables relate to