问题
I have a text field, which will accept only the following characters:
Allowed characters: [a-z 0-9 + # - .]
This is the same filter SO does in the 'Tags' field, when you're asking a question. If the user types an invalid character, i want the current text field value to remain unchanged. I tried:
$('#post_tags').keypress(function(event){
var char = String.fromCharCode(event.which)
var txt = $(this).val()
if (! txt.match(/[^A-Za-z0-9+#-\.]/)){
$(this).val(txt.replace(char, ''));
}
})
Why it doesn't work? Thanks!
回答1:
/[^A-Za-z0-9+#-\.]/
This negates the match of any one of those characters. To make it match more than one character, you have to use a +
in there:
/[^A-Za-z0-9+#-\.]+/
^
And now to match the whole string, you need to add anchors:
/^[^A-Za-z0-9+#-\.]+$/
^ ^
EDIT: Okay, it seems that the -
here is also creating a range from character #
to .
. In this case, you can either escape it, or put it at the end:
/^[^A-Za-z0-9+#\-\.]+$/
/^[^A-Za-z0-9+#\.-]+$/
回答2:
This worked for me:
$(function(){
$('#t').keypress(function(e){
var txt = String.fromCharCode(e.which);
console.log(txt + ' : ' + e.which);
if(!txt.match(/[A-Za-z0-9+#.]/))
{
return false;
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input id="t" />
回答3:
Alternate Solution
One thing that might help would be to use the .which
field instead. Then simply return false when it doesn't fit. I actually have a huge object full of .which info for all major browsers. It includes arrays you could borrow from it to create something like:
var alphaNumericNcontrols = [ 8,9,13,16,17,18,19,20,32,33,34,35,36,37,38,39,40,44,45,46,145,48,49,50,51,52,53,54,55,56,57,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,96,97,98,99,100,101,102,103,104,105 ],
illegal = {
reg: [ 106,111,191,220 ],
shift: [ 56,59,188,190,191,220,222 ]
}
$(document).on("keydown", "input[type=text]", function(e) {
var eKey = e.which || e.keyCode;
if (alphaNumericNcontrols.indexOf(eKey) === -1) return false;
if (illegal.reg.indexOf(eKey) > -1) return false;
if (e.shiftKey && illegal.shift.indexOf(eKey) > -1) return false;
});
See Working Example Here
Keep in mind my Object is not perfect and there are some updates I probably need to make to it, but i did my best to establish everything from every possible major browser!
回答4:
Thanks everyone.
Actually my problem was a little more difficult: filter invalid keys and start a ajax call for valid ones, in 2 different ways: if the user press SPACE/COMMA or while he/her still typing. Here's the code:
$(document).ready(function(){
$('#post_tags').keypress(function(e){
var txt = String.fromCharCode(e.which);
console.log(txt + ' : ' + e.which);
if(txt.match(/^[^A-Za-z0-9+#\-\.]+$/))
{
return false;
}
})
$('#post_tags').keyup(function(event){
code = event.which
var token = String.fromCharCode(code)
var txt = $(this).val()
//create a new tag, take it out of textfield
if (code == 32 || code == 188)
{
console.log("AJAX new word keyup")
$.ajax({
type: 'get',
url: '/posts/tags_change',
dataType: "json",
data: "query=" + $(this).val(),
success: function(data) {
console.log(data)
$('#post_tags').val('')
},
error: function(data) {
alert("Ajax error")
}
});
}
else
{
//do autocomplete ajax
console.log("typing:" + txt)
}
});
})
Dont' know if this is 100% right!
回答5:
You don't need to replace the char, only prevent it.
var char = String.fromCharCode(event.which)
if (!char.match(/^[^A-Za-z0-9+#\.\-]+$/)) event.preventDefault();
来源:https://stackoverflow.com/questions/17220667/jquery-filter-input-on-keypress