问题
I'm trying to replicate, roughly, the dplyr package from R using Python/Pandas (as a learning exercise). Something I'm stuck on is the "piping" functionality.
In R/dplyr, this is done using the pipe-operator %>%, where x %>% f(y) is equivalent to f(x, y). If possible, I would like to replicate this using infix syntax (see here).
To illustrate, consider the two functions below.
import pandas as pd
def select(df, *args):
cols = [x for x in args]
df = df[cols]
return df
def rename(df, **kwargs):
for name, value in kwargs.items():
df = df.rename(columns={'%s' % name: '%s' % value})
return df
The first function takes a dataframe and returns only the given columns. The second takes a dataframe, and renames the given columns. For example:
d = {'one' : [1., 2., 3., 4., 4.],
'two' : [4., 3., 2., 1., 3.]}
df = pd.DataFrame(d)
# Keep only the 'one' column.
df = select(df, 'one')
# Rename the 'one' column to 'new_one'.
df = rename(df, one = 'new_one')
To achieve the same using pipe/infix syntax, the code would be:
df = df | select('one') \
| rename(one = 'new_one')
So the output from the left-hand side of | gets passed as the first argument to the function on the right-hand side. Whenever I see something like this done (here, for example) it involves lambda functions. Is it possible to pipe a Pandas' dataframe between functions in the same manner?
I know Pandas has the .pipe method, but what's important to me is the syntax of the example I provided. Any help would be appreciated.
回答1:
It is hard to implement this using the bitwise or operator because pandas.DataFrame implements it. If you don't mind replacing | with >>, you can try this:
import pandas as pd
def select(df, *args):
cols = [x for x in args]
return df[cols]
def rename(df, **kwargs):
for name, value in kwargs.items():
df = df.rename(columns={'%s' % name: '%s' % value})
return df
class SinkInto(object):
def __init__(self, function, *args, **kwargs):
self.args = args
self.kwargs = kwargs
self.function = function
def __rrshift__(self, other):
return self.function(other, *self.args, **self.kwargs)
def __repr__(self):
return "<SinkInto {} args={} kwargs={}>".format(
self.function,
self.args,
self.kwargs
)
df = pd.DataFrame({'one' : [1., 2., 3., 4., 4.],
'two' : [4., 3., 2., 1., 3.]})
Then you can do:
>>> df
one two
0 1 4
1 2 3
2 3 2
3 4 1
4 4 3
>>> df = df >> SinkInto(select, 'one') \
>> SinkInto(rename, one='new_one')
>>> df
new_one
0 1
1 2
2 3
3 4
4 4
In Python 3 you can abuse unicode:
>>> print('\u01c1')
ǁ
>>> ǁ = SinkInto
>>> df >> ǁ(select, 'one') >> ǁ(rename, one='new_one')
new_one
0 1
1 2
2 3
3 4
4 4
[update]
Thanks for your response. Would it be possible to make a separate class (like SinkInto) for each function to avoid having to pass the functions as an argument?
How about a decorator?
def pipe(original):
class PipeInto(object):
data = {'function': original}
def __init__(self, *args, **kwargs):
self.data['args'] = args
self.data['kwargs'] = kwargs
def __rrshift__(self, other):
return self.data['function'](
other,
*self.data['args'],
**self.data['kwargs']
)
return PipeInto
@pipe
def select(df, *args):
cols = [x for x in args]
return df[cols]
@pipe
def rename(df, **kwargs):
for name, value in kwargs.items():
df = df.rename(columns={'%s' % name: '%s' % value})
return df
Now you can decorate any function that takes a DataFrame as the first argument:
>>> df >> select('one') >> rename(one='first')
first
0 1
1 2
2 3
3 4
4 4
Python is awesome!
I know that languages like Ruby are "so expressive" that it encourages people to write every program as new DSL, but this is kind of frowned upon in Python. Many Pythonists consider operator overloading for a different purpose as a sinful blasphemy.
[update]
User OHLÁLÁ is not impressed:
The problem with this solution is when you are trying to call the function instead of piping. – OHLÁLÁ
You can implement the dunder-call method:
def __call__(self, df):
return df >> self
And then:
>>> select('one')(df)
one
0 1.0
1 2.0
2 3.0
3 4.0
4 4.0
Looks like it is not easy to please OHLÁLÁ:
In that case you need to call the object explicitly:
select('one')(df)Is there a way to avoid that? – OHLÁLÁ
Well, I can think of a solution but there is a caveat: your original function must not take a second positional argument that is a pandas dataframe (keyword arguments are ok). Lets add a __new__ method to our PipeInto class inside the docorator that tests if the first argument is a dataframe, and if it is then we just call the original function with the arguments:
def __new__(cls, *args, **kwargs):
if args and isinstance(args[0], pd.DataFrame):
return cls.data['function'](*args, **kwargs)
return super().__new__(cls)
It seems to work but probably there is some downside I was unable to spot.
>>> select(df, 'one')
one
0 1.0
1 2.0
2 3.0
3 4.0
4 4.0
>>> df >> select('one')
one
0 1.0
1 2.0
2 3.0
3 4.0
4 4.0
回答2:
While I can't help mentioning that using dplyr in Python might the closest thing to having in dplyr in Python (it has the rshift operator, but as a gimmick), I'd like to also point out that the pipe operator might only be necessary in R because of its use of generic functions rather than methods as object attributes. Method chaining gives you essentially the same without having to override operators:
dataf = (DataFrame(mtcars).
filter('gear>=3').
mutate(powertoweight='hp*36/wt').
group_by('gear').
summarize(mean_ptw='mean(powertoweight)'))
Note wrapping the chain between a pair of parenthesis lets you break it into multiple lines without the need for a trailing \ on each line.
回答3:
You can use sspipe library, and use the following syntax:
from sspipe import p
df = df | p(select, 'one') \
| p(rename, one = 'new_one')
回答4:
I couldn't find a built-in way of doing this, so I created a class that uses the __call__ operator because it supports *args/**kwargs:
class Pipe:
def __init__(self, value):
"""
Creates a new pipe with a given value.
"""
self.value = value
def __call__(self, func, *args, **kwargs):
"""
Creates a new pipe with the value returned from `func` called with
`args` and `kwargs` and it's easy to save your intermedi.
"""
value = func(self.value, *args, **kwargs)
return Pipe(value)
The syntax takes some getting used to, but it allows for piping.
def get(dictionary, key):
assert isinstance(dictionary, dict)
assert isinstance(key, str)
return dictionary.get(key)
def keys(dictionary):
assert isinstance(dictionary, dict)
return dictionary.keys()
def filter_by(iterable, check):
assert hasattr(iterable, '__iter__')
assert callable(check)
return [item for item in iterable if check(item)]
def update(dictionary, **kwargs):
assert isinstance(dictionary, dict)
dictionary.update(kwargs)
return dictionary
x = Pipe({'a': 3, 'b': 4})(update, a=5, c=7, d=8, e=1)
y = (x
(keys)
(filter_by, lambda key: key in ('a', 'c', 'e', 'g'))
(set)
).value
z = x(lambda dictionary: dictionary['a']).value
assert x.value == {'a': 5, 'b': 4, 'c': 7, 'd': 8, 'e': 1}
assert y == {'a', 'c', 'e'}
assert z == 5
来源：https://stackoverflow.com/questions/33658355/piping-output-from-one-function-to-another-using-python-infix-syntax