push() a two-dimensional array

问题

I'm trying to push to a two-dimensional array without it messing up, currently My array is:

var myArray = [
[1,1,1,1,1],
[1,1,1,1,1],
[1,1,1,1,1]
]

And my code I'm trying is:

var r = 3; //start from rows 3
var c = 5; //start from col 5

var rows = 8;
var cols = 7;

for (var i = r; i < rows; i++)
{
    for (var j = c; j < cols; j++)
    {
        myArray[i][j].push(0);
    }
}

That should result in the following:

var myArray = [
[1,1,1,1,1,0,0],
[1,1,1,1,1,0,0],
[1,1,1,1,1,0,0],
[0,0,0,0,0,0,0],
[0,0,0,0,0,0,0],
[0,0,0,0,0,0,0],
]

But it doesn't and not sure whether this is the correct way to do it or not.

So the question is how would I accomplish this?

回答1:

You have some errors in your code:

Use myArray[i].push( 0 ); to add a new column. Your code (myArray[i][j].push(0);) would work in a 3-dimensional array as it tries to add another element to an array at position [i][j].
You only expand (col-d)-many columns in all rows, even in those, which haven't been initialized yet and thus have no entries so far.

One correct, although kind of verbose version, would be the following:

var r = 3; //start from rows 3

var rows = 8;
var cols = 7;

// expand to have the correct amount or rows
for( var i=r; i<rows; i++ ) {
  myArray.push( [] );
}

// expand all rows to have the correct amount of cols
for (var i = 0; i < rows; i++)
{
    for (var j =  myArray[i].length; j < cols; j++)
    {
        myArray[i].push(0);
    }
}

回答2:

You have to loop through all rows, and add the missing rows and columns. For the already existing rows, you loop from c to cols, for the new rows, first push an empty array to outer array, then loop from 0 to cols:

var r = 3; //start from rows 3
var c = 5; //start from col 5

var rows = 8;
var cols = 7;

for (var i = 0; i < rows; i++) {
  var start;
  if (i < r) {
    start =  c;
  } else {
    start = 0;
    myArray.push([]);
  }
  for (var j = start; j < cols; j++) {
        myArray[i].push(0);
    }
}

回答3:

Iterating over two dimensions means you'll need to check over two dimensions.

assuming you're starting with:

var myArray = [
    [1,1,1,1,1],
    [1,1,1,1,1],
    [1,1,1,1,1]
]; //don't forget your semi-colons

You want to expand this two-dimensional array to become:

var myArray = [
    [1,1,1,1,1,0,0],
    [1,1,1,1,1,0,0],
    [1,1,1,1,1,0,0],
    [0,0,0,0,0,0,0],
    [0,0,0,0,0,0,0],
    [0,0,0,0,0,0,0],
];

Which means you need to understand what the difference is.

Start with the outer array:

var myArray = [
    [...],
    [...],
    [...]
];

If you want to make this array longer, you need to check that it's the correct length, and add more inner arrays to make up the difference:

var i,
    rows,
    myArray;
rows = 8;
myArray = [...]; //see first example above
for (i = 0; i < rows; i += 1) {
    //check if the index exists in the outer array
    if (!(i in myArray)) {
        //if it doesn't exist, we need another array to fill
        myArray.push([]);
    }
}

The next step requires iterating over every column in every array, we'll build on the original code:

var i,
    j,
    row,
    rows,
    cols,
    myArray;
rows = 8;
cols = 7; //adding columns in this time
myArray = [...]; //see first example above
for (i = 0; i < rows; i += 1) {
    //check if the index exists in the outer array (row)
    if (!(i in myArray)) {
        //if it doesn't exist, we need another array to fill
        myArray[i] = [];
    }
    row = myArray[i];
    for (j = 0; j < cols; j += 1) {
        //check if the index exists in the inner array (column)
        if (!(i in row)) {
            //if it doesn't exist, we need to fill it with `0`
            row[j] = 0;
        }
    }
}

回答4:

In your case you can do that without using push at all:

var myArray = [
    [1,1,1,1,1],
    [1,1,1,1,1],
    [1,1,1,1,1]
]

var newRows = 8;
var newCols = 7;

var item;

for (var i = 0; i < newRows; i++) {
    item = myArray[i] || (myArray[i] = []);

    for (var k = item.length; k < newCols; k++)
        item[k] = 0;    
}

回答5:

var r = 3; //start from rows 3
var c = 5; //start from col 5

var rows = 8;

var cols = 7;


for (var i = 0; i < rows; i++)

{

 for (var j = 0; j < cols; j++)

 {
    if(j <= c && i <= r) {
      myArray[i][j] = 1;
    } else {
      myArray[i][j] = 0;
    }
}

}

回答6:

you are calling the push() on an array element (int), where push() should be called on the array, also handling/filling the array this way makes no sense you can do it like this

for (var i = 0; i < rows - 1; i++)
{
  for (var j = c; j < cols; j++)
  {
    myArray[i].push(0);
  }
}


for (var i = r; i < rows - 1; i++)
{

  for (var j = 0; j < cols; j++)
  {
      col.push(0);
  }
}

you can also combine the two loops using an if condition, if row < r, else if row >= r

回答7:

Create am array and put inside the first, in this case i get data from JSON response

$.getJSON('/Tool/GetAllActiviesStatus/',
   var dataFC = new Array();
   function (data) {
      for (var i = 0; i < data.Result.length; i++) {
          var serie = new Array(data.Result[i].FUNCAO, data.Result[i].QT, true, true);
          dataFC.push(serie);
       });

来源：https://stackoverflow.com/questions/11345954/push-a-two-dimensional-array

标签

javascript

arrays

for-loop

multidimensional-array

push