问题
I have a model that is composed of three case classes as below:
case class MyModel(myId: MyIdType, name: MyNameType)
case class MyIdType(id: Long)
case class MyNameType(name: String)
object MyNameType(name: String) {
val NAME1 = MyNameType("name1")
val NAME2 = MyNameType("name2")
val NAME3 = MyNameType("name3")
}
Let's say these are the existing models. I have a Slick table mapping that goes like this:
class MyTable(tag: Tag) extends Table[MyTableElem](tag, "myTable") {
def id = column[Long]("id", O.PrimaryKey)
def name = column[String]("name")
def * = (id, name) <> (MyTableElem.tupled, MyTableElem.unapply)
}
As it can be seen that I have to have another type to map my table MyTable first to MyTableElem and then during every read, I transform the MyTableElem to MyModel. Is there a way to avoid this and go directly to the MyModel? I guess I have to implement the tupled and unapply methods or?
回答1:
I think you may have to define your own column type. In Slick 3.0 documentation Using Custom Scalar Types in Queries,
MappedTo
could be used in your case.
If you have a wrapper class (which can optionally be a case class and/or value class) for an underlying value of some supported type, you can make it extend MappedTo to get a macro-generated implicit ColumnType for free.
Following is how I try to get your problem done.
import slick.lifted.Tag
// I am using PostgreSQL
import slick.driver.PostgresDriver.api._
case class MyModel(myId: MyIdType, name: MyNameType)
case class MyIdType(id: Long) extends MappedTo[Long] {
override def value: Long = id
}
case class MyNameType(name: String) extends MappedTo[String] {
override def value: String = name
}
class MyTable(tag: Tag) extends Table[MyModel](tag, "myTable") {
def id = column[MyIdType]("id", O.PrimaryKey)
def name = column[MyNameType]("name")
def * = (id, name) <> (MyModel.tupled, MyModel.unapply)
}
Anyway, hope it helps.
来源:https://stackoverflow.com/questions/32628389/slick-3-0-0-mapping-existing-models